Same would need to get at least a 95% on the next test, if he would like to receive a total average of an 80%
Answer:75%
Step-by-step explanation:
48 over 64 & x over 100
100•48 =4800/64= 75
Answer:
3x-5> 6x- 14
Step-by-step explanation:
Let the blue ribbons be denoted by the letter x.
Then according to the given condition
3 times the blue ribbons = 3x
Decreased by 5 = 3x-5
is greater than
6 times the blue ribbons = 6x
decreased by 14 = 6x-14
Putting in one line
3x-5> 6x- 14
Solving the inequality
3x-5> 6x- 14
Taking both sides positive as in modulus
14-5 > 6x-3x
9> 3x
9/3 > x
3> x
Again solving for inequality
3x-5> 6x- 14
Taking one side negative that is mod
3x-5> -6x + 14
3x+ 6x > 14+5
9x> 19
x > 19/9
x > 2.11
so x lies between 2 and 3
3 > x > 2.11
Now putting the values for x= 19
3x-5> 6x- 14
57-5> 114-14
52 > 100 False
Now putting the values for x= 3
3x-5> 6x- 14
9-5> 18-14
4>4 False
Now putting the values for x= 2
3x-5> 6x- 14
6-5> 12-14
1> -2 True
There are 2 blue ribbons
Answer:
proportion of gamers who prefer console does not differ from 29%
Step-by-step explanation:
Given :
n = 341 ; x = 95 ; Phat = x / n = 95/341 = 0.279
H0 : p = 0.29
H1 : p ≠ 0.29
The test statistic :
T = (phat - p) ÷ √[(p(1 - p)) / n]
T = (0.279 - 0.29) ÷ √[(0.29(1 - 0.29)) / 341]
T = (-0.011) ÷ √[(0.29 * 0.71) / 341]
T = -0.011 ÷ 0.0245725
T = - 0.4476532
Using the Pvalue calculator from test statistic score :
df = 341 - 1 = 340
Pvalue(-0.447, 340) ; two tailed = 0.654
At α = 0.01
Pvalue > α ; We fail to reject the null and conclude that there is no significant evidence that proportion of gamers who prefer console differs from 29%
