7*6*x^-8*x^3
42x^-8+3 (bases same powers add)
42x^-5
1/42x^5
<span>so the simplified </span>form<span> of 7x^-8*6x^3 is=1/42x^5</span>
Answer:
3/2
Step-by-step explanation:
The quadrants in which all the coordinates given are located is; As explained below.
<h3>How to Identify Quadrants in coordinates?</h3>
1) (2, 4) is located in Quadrant I where both x and y-values are positive.
2) (0, -3) is located in Quadrant II where x - values are positive but y-values are negative.
3) (-1, 1/2) is located in Quadrant IV.
4) (-2 1/2, -7) is located in Quadrant III where x and y values are both negative.
5) (0, 6) is located in Quadrant I where both x and y-values are positive.
6) (-5, 0) is located in Quadrant IV where x is negative but y is positive.
Read more about Quadrant Coordinates at; brainly.com/question/863849
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<h3><u>The unknown number is equal to 4.</u></h3>
8x - 27 = 5
Add 27 to both sides.
8x = 32
Divide both sides by 8
x = 4
20×8=160
5×8=40
10×8=80
4×8=32
15×8=120
160+40+80+120+32=432
432×2=864
864 is the answer,so your answer is b
