Answer:
p=-7 :)
Step-by-step explanation:
-13-8=3p
-13+(-8)=3p
-21=3p
÷3
-7=p
The answer is 16 bc yeah i said it was
Basically what you need to do is:
3000 X 0.04^3
I would give an answer but I don’t have a calculator at the moment, but I hope this helps
Answer:
<h2>
4773 peoples.</h2>
Step-by-step explanation:
Given the number of people d, in thousands applying for medical benefits per week in a particular city c modeled by the equation d(t)=2.5 sin(0.76t+0.3)+3.8 where t is the time in years, the maximum number of people tat will apply will occur at d(t)/dt = 0
Differentiating the function given with respect to t, we will have;

First we need to know that differential of any constant is zero.

If
then;

To know the maximum number of people in thousands that apply for benefits per year in the city, we wil substitute the value of t = 29.75 into the modeled equation

Since d is in thousands, the maximum number of people in thousands will be 4.7732*1000 = 4773.2 which is approximately 4773 peoples.
Answer:
-64
Step-by-step explanation:
Given expression

Perform all multiplications and divisions:

Now subtract results in brackets:

Now, divide:
