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mrs_skeptik [129]
3 years ago
12

Write two equivalent expressions to the following radical expression: (√104 * √124)8

Mathematics
1 answer:
CaHeK987 [17]3 years ago
3 0

Answer:

HERES ONE

ANSWER=1053.34


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Absolute value is the number's distance from 5 on a number line.<br> True<br> False
wlad13 [49]

Answer:

True

Step-by-step explanation:

I'm also reporting the previous answer that had a link, mark me as brainliest, not the cutt link or whatever link that is because i somehow know that it's wrong

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3 years ago
Read 2 more answers
The Toylot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A) under a norma
kotegsom [21]

Answer:

Test statistic = 3.1587

Step-by-step explanation:

We are given that the Toy-lot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A).

Also, a sample of eleven motors was tested, and it was found that the mean current was x = 1.20 A, with a sample standard deviation of s = 0.42 A.

So, Null Hypothesis, H_0 : \mu = 0.8 { claim of 0.8 A is not low}

Alternate Hypothesis, H_1 : \mu > 0.8 { claim of 0.8 A is too low}

Now, the test statistics used here will be;

           T.S. = \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 1.20 A

                 s = sample standard deviation = 0.42 A

                 n = sample size = 11 motors

So, Test statistics = \frac{1.20 - 0.8}{\frac{0.42}{\sqrt{11} } } ~ t_1_0

                             = 3.1587

At 1% level of significance, t table gives a critical value of 2.764 at 10 degree of freedom. Since our test statistics is higher than the critical value so we have sufficient evidence to reject null hypothesis .

Therefore, we conclude that Toy-lot claim of 0.8 A is too low.

8 0
4 years ago
3. Slope -2, Point = (4.-6). Write the
IrinaVladis [17]
Y=-2x-6. B is the y intercept, so I think it would be -6 from the point.
7 0
3 years ago
What is the correct answer of evaluate the expression 2 to the fifth power​
ANEK [815]

2^5 = 2×2×2×2×2

= 4×2×2×2

=8×2×2

=16×2

=32

4 0
4 years ago
According to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation, there were over 71 million wildif
suter [353]

Answer:

The probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is P=0.412.

Step-by-step explanation:

We know the population proportion π=0.8, according to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation.

If we take a sample from this population, and assuming the proportion is correct, it is expected that the sample's proportion to be equal to the population's proportion.

The standard deviation of the sample is equal to:

\sigma_s=\sqrt{\frac{\pi(1-\pi)}{N}}=\sqrt{\frac{0.8*0.2}{500}}=0.018

With the mean and the standard deviaion of the sample, we can calculate the z-value for 0.79 and 0.81:

z=\frac{p-\pi}{\sigma}=\frac{0.79-0.80}{0.018} =\frac{-0.01}{0.018} = -0.55\\\\z=\frac{p-\pi}{\sigma}=\frac{0.81-0.80}{0.018} =\frac{0.01}{0.018} = 0.55

Then, the probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is:

P(0.79

3 0
3 years ago
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