I think the rate is decreasing from:
(-infinity, ln9/3)
(xy)' + (2x)' + (3x^2)' = (4)'
y + xy' + 2 + 6x = 0
xy' = -y -2 -6x
y' = [-y -2 -6x] / x
Now solve y from the original equation and substitue
xy + 2x + 3x^2 = 4 => y = [-2x - 3x^2 + 4] / x
y' = [(-2x - 3x^2 +4) / x - 2 - 6x ] / x
y' = [-2x - 3x^2 + 4 -2x -6x^2 ] x^2 = [ -4x - 9x^2 + 4] / x^2 =
= [-9x^2 - 4x + 4] / x^2
The positive x axis in polar coordinates is called a pole
Tim
practices his backhand and his serve at least 2 hours each day this means
X =<
2 ( less than or equal to 2 hrs)
<span>He
works less on his backhand than his serve and practices his serve more than
hour daily. </span>
<span>Y <
1</span>
