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Anettt [7]
3 years ago
6

latrell wants to keep his test average in his class at 85 or higher. so far, he has earned score of 85, 76, 94 and 81 on his tes

ts. whqt score must he get on his test to keep his average at 85+or higher
Mathematics
1 answer:
Lena [83]3 years ago
7 0

Answer:

89

Step-by-step explanation:

Use the mean formula, mean = sum of elements / number of elements.

He wants to keep his average at 85 or higher, so plug in 85 as the mean. Let x represent the score he has to get, and solve for x:

mean = sum of elements / number of elements.

85 = (85 + 76 + 94 + 81 + x) / 5

85 = (336 + x) / 5

425 = 336 + x

89 = x

So, he has to get a 89.

You might be interested in
The industrial process that is used to convert a fuel to gasoline is carried out at a temperature range of 660 degrees°F to 790
NARA [144]

Answer:

|F-725|

With F represent the variable of interest:

-65< F-725< 65

-65+725< F< 65+725

660 < F< 790

Step-by-step explanation:

For this case we have a normal limits for the temperature Range. The minimum is 660 F and the maximum 790 F.

We can find the midpoint of this interval like this:

Midpoint= \frac{660+790}{2}= 725

And the difference between the midpoint and the limits are:

|790-725|= 65

|680-725|= 65

So then we can create the following inequality:

|F-725|

With F represent the variable of interest.:

-65< F-725< 65

-65+725< F< 65+725

660 < F< 790

5 0
3 years ago
a car reduced its speed in a ratio of 2 to 3 if the final speed was 90 km per hour then what was the original speed.​
Licemer1 [7]

Answer:

Orginal Speed is 135

Step-by-step explanation:

The ratio of final speed: original speed is

\frac{2}{3\\}

We know that 90 km is it final speed so, we set up a proportion

\frac{2}{3} =90/x

2x=270\\x=135

8 0
2 years ago
Find a number if 10/9 of it is 10
grandymaker [24]

Answer:

ok

umm

so 11?

Step-by-step explanation:

:(

6 0
3 years ago
Please answer the question, I think I have the answer but I'm not sure.
Georgia [21]

Answer:

20cm

Step-by-step explanation:

Frame L&W: 25×20

PictureL&W:20×16

25-20=5

Length of Picture frame=5

Length of Picture frame=4

5×4=20cm²

To find area you multiply length by width

8 0
3 years ago
Complete the data set with one value so that the mean of the data is 7.
zlopas [31]
Add 2
Remove 8.........
6 0
3 years ago
Read 2 more answers
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