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Margarita [4]
3 years ago
15

Can someone help me asap. ​

Mathematics
2 answers:
s2008m [1.1K]3 years ago
6 0

Answer:

option 1

Step-by-step explanation:

\sqrt{y} =y^{\frac{1}{2}}\\\\(\frac{1}{\sqrt{y} })^{\frac{-1}{5}} =(\frac{1}{y^{\frac{1}{2}}})^{\frac{-1}{5}}\\\\= (y^{\frac{-1}{2}})^{\frac{-1}{5}}\\\\=y^{\frac{-1}{2}*\frac{-1}{5}}\\\\= y^{\frac{1}{10}}\\\\=\sqrt[10]{y}

dalvyx [7]3 years ago
4 0

Answer:

-  \frac{1}{5 \sqrt{y} }

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Answer:

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Step-by-step explanation:

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2 years ago
Which ordered pair is included in the solution set to the following system?
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The ordered pair is included in the solution set to the following system is (0,2)

<h3>Set of inequalities</h3>

Given the set of inequalities

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This shows that the ordered pair is included in the solution set to the following system is (0,2)

Learn more on inequality here: brainly.com/question/24372553

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