Answer:
Jaundice is a symptom of cirhosis which is related to the chronic liver disease
Explanation:
Bilirubin is produced in the body when the hemoglobin protein in old red blood cells is broken down. Erythrocytes continuously undergo a (breaking apart) process. As the red blood cells disintegrate, the hemoglobin is degraded or broken into globin (the protein part), iron, and heme. The heme first breaks apart into biliverdin, a green pigment which is immediately reduced to bilirubin, an orange-yellow pigment. The bilirubin is then transported to the liver where it reacts with a solubilizing sugar called glucuronic acid. This more soluble form of bilirubin (conjugated) is excreted into the bile. The bile passes through the gall bladder then goes into the intestines where the bilirubin is converted into a variety of pigments.
Jaundice occurs when the diseased liver doesn't remove enough bilirubin, a blood waste product, from your blood. Cirrhosis, when in its late stages, can cause Jaundice. Cirrhosis occurs as a result of severe scarring of the liver caused by chronic liver disease. As a healthy liver tissue becomes damaged over time, it is replaced by scar tissue, which affects the structure of the liver and decreasing its ability to function.
Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross
The expression of genes in an organism can be influenced by the environment, adding the external world in which the organism is or where it develops, as well as the organism's internal world, which includes such factors as its hormones and metabolism.
Answer: the brain scans showed that there were areas of damage in the brains of all but one of the Mexico City kids. The damage was caused by air pollution.
The answer is <span>xylem and phloem.
Xylem and phloem are the transport tissues of vascular plants. </span><span>Parenchyma and collenchyma are ground tissue, while pith and cortex are stem tissue.
</span><span>Xylem and phloem provide transportation of water, minerals, food, and nutrients. Xylem transport water and minerals from the root to the upper parts of the plant. Phloem transports food and nutrients from the leaves, where they are produced, to the growing or storage parts of the plants.
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