9514 1404 393
Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
3 rows of 12
9 rows of 4
2 rows of 18
6 rows of 6
Answer:
8 times larger
Step-by-step explanation:
4 ·
= 4 · 10 · 10 · <u>10</u> · <u>10</u> · <em>10</em> · <em>10</em> · 10
4 · 100 · <u>100</u> · <em>100</em> · 10
400 · 10000 · 10
= 40000000
5 ·
= 5 · 10 · 10 · <u>10</u> · <u>10</u> · 10
50 · 100 · <u>100</u> · 10
5000 · 1000
= 5000000
40000000 ÷ 5000000 = 8
One time because 50 x 50 equals 100 and that to large