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Bad White [126]
3 years ago
8

A parking lot is 20 feet long. One tortoise starts at the edge of the parking lot and moves at a rate of 6 feet per minute. Anot

her tortoise starts 4 feet from the edge of the parking lot and moves 2 feet per minute. Write an equation to represent when they will be in the same spot.
Mathematics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

Kindly check explanation

Step-by-step explanation:

Length of parking lot = 20 feets

Speed of tortoise which starts at the edge = 6 feets per minute

Speed of tortoise which starts 4 feets from the edge = 2 feets per minute

Equation to represent when they will be in the same spot.

Distance = speed * time

Distance of Tortoise at edge = 6ft/min * t = 6t - - (1)

Distance of the other tortoise = (4 + 2t) - - - (2)

Equating both (1) and (2)

6t = 4 + 2t

6t - 2t = 4

4t = 4

t = 4/4

t = 1

Hence, they'll be at the same spot after 1 minute.

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The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

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Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

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35                      40.00                         0.62

35                      28.0                          1.75

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25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

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Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

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AB> (A)(B)/N  

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35> 1500/200

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and so on.

Hence they are positively associated

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