And the angle of the obtuse angle formed at the intersection of AV and HI is 104°
Step-by-step explanation: starting with m<MIH, AH is parallel to MI, so that would make the same angle H has the same for I. (34°)
Next is m<AVM. The angle of m<LAH is 110°. So the angle of m<HAV (because it's supplementary of it) is 70 (110+70=180). Which makes m<AVM 70° since it's vertical to each other.
Since we got those answers, the next one you just plug it in, and the answer would be 104°
