We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
The estimate would be 2+3 5+2 and 6+1
so 577
you can also just round and do 250 +300= 550 +20=570
Answer:
2,196; 549; 131.76; 8; 175.68; 1339.56
Step-by-step explanation:
2,196 is the biggest number, so use that as the first number.
.25x2196=549
.06x2196=131.76
.08x2196=175.68
2196-(549+131.76+175.68)=1339.56
I think the answer is c, 88
Hope this helps :)
