step 1
<u>Find the number of miles run by each bus in one day</u>
we know that
speed=distance/time
distance=speed*time
distance=(15 mi/h)*3 h=45 miles
<u>Find the number of miles run by the total buses in one day</u>
Multiply by 300
300*45=13,500 miles
<u>Find the number of miles run by the total buses in 22 days</u>
13,500*22=297,000 miles
step 2
<u>Find the number of gallons to run 297,000 miles</u>
we know that
the fuel economy of the buses is 10 mi/gal
so
by proportion

step 3
<u>Find the cost of 29,700 gal of gasoline</u>
we know that
the gasoline costs $4.10 per gallon
then
29,700*4.10=$121,770
therefore
<u>the answer is</u>
the cost of the gasoline is $121,770
Answer:
(3, 3 )
Step-by-step explanation:
Given the 2 equations
3x - y = 6 → (1)
6x + y = 21 → (2)
Adding the 2 equations term by term will eliminate y, that is
(6x + 3x) + (y - y) = (21 + 6), that is
9x = 27 (divide both sides by 9 )
x = 3
Substitute x = 3 into either (1) or (2) and solve for y
Using (2), then
(6 × 3) + y = 21
18 + y = 21 ( subtract 18 from both sides )
y = 3
Solution is (3, 3 )
I can help with the first problems!
Answer:
Marna needs to answer correctly 17 times.
Step-by-step explanation:
-5 * 17 = -85, anything lower won't work.
12x2=24
The middle is extra. All you need to answer is the $12 is half his allowence left.