Answer:
D. 2058.24 in³
Step-by-step explanation:
Let r,h be the radius and height of smaller can and R,H be the radius and height of larger can
Then, R=4r and H=4h
Volume of smaller can=32.16 in³
⇒ πr²h=32.16 in³
Volume of larger can= πR²H
= π(4r²)×4h
= 64πr²h
= 64×32.16 in³
= 2058.24 in³
Hence, correct option is:
D. 2058.24 in³
m∠AOC = m∠AOB + m∠BOC
We have m∠AOC = 19°, m∠AOB = 4x - 15 and m∠BOC = 2x + 10. Substitute:
19 = (4x - 15) + (2x + 10)
19 = (4x + 2x) + (-15 + 10)
19 = 6x - 5 <em>add 5 to both sides</em>
24 = 6x <em>divide both sides by 6</em>
4 = x
m∠BOC = 2x + 10 → m∠BOC = 2(4) + 10 = 8 + 10 = 18
m∠AOB = 4x - 15 → m∠AOB = 4(4) - 15 = 16 - 15 = 1
<h3>Answer: c. m∠BOC = 18°, m∠AOB = 1°</h3>
B, since 13 ppl have 2 or less TVs while 12 have 3 or more
Answer:
There is a reason for ✨Infromational webstites ✨ your welcome!
174325 rounded to the nearest ten thousand is 170,000
hope this helps
