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icang [17]
3 years ago
13

Re-write the quadratic function below in Standard Form y=-3 (x - 2)² – 7

Mathematics
1 answer:
pav-90 [236]3 years ago
3 0

Answer:

y=-3x^2+12x-19

Step-by-step explanation:

we know that

The quadratic equation in standard form is equal to

y=ax^{2} +bx+c

we have

y=-3(x-2)^{2}-7

This is a quadratic equation in vertex form

Convert to standard form

y=-3(x^2-4x+4)-7

Apply distributive property

y=-3x^2+12x-12-7

Combine like terms

y=-3x^2+12x-19 ----> quadratic equation in standard form

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The frequency distribution chart below represents scores from a math quiz.
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The frequency distribution chart of the math quiz has a data that is skewed left.

<h3>How to interpret the shape of the histogram?</h3>

From the complete question (see attachment for histogram), we have the following highlight:

The dataset on the right-hand side is taller than those on the left.

This means that the dataset is skewed left.

Hence, the statement that best describes the data is (a) The data is skewed left.

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Last one promise.Please help me.
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The answer is 240.5  hope you get the question
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4. 65% of 80 is what number?
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Answer:3.72

Step-by-step explanation:

80x.465 is the equation

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1.325 to the nearest hundreths
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1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)

n(X ∪ Y ∪ C') = 145-50

n(X ∪ Y ∪ C') = 95

6 0
3 years ago
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