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sweet-ann [11.9K]
3 years ago
11

An object carrying a force of 15N has a mass of 3kg. What is the acceleration of this object?

Physics
1 answer:
Sedaia [141]3 years ago
8 0

Answer:

the acceleration would be 5kg

Explanation:because you would do 15 divided by 5

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A mineral has the following properties: low hardness (can't scratch a penny), red color and streak, low specific gravity (densit
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Answer:as a coloring (pigment) in makeup or paint

Explanation:

4 0
3 years ago
Charge is moving through a wire. An amount of charge Q moves past a particular spot in the wire in an amount of time t to produc
Blababa [14]

We will apply the concept related to the current change given in the same problem. We will divide both currents into two states: the new current and the old current. As the current is the change of the load in a certain time, we will have that the old current is,

I_{old} = \frac{dq}{dt}

If it takes 5 times more time, then we will have the new current is,

I_{new} = \frac{dq}{5dt}

I_{new} = \frac{1}{5}(\frac{dq}{dt})

Replacing the given value of the old current we will have to,

I_{new} = \frac{I_{old}}{5}

Therefore the new current will be \frac{1}{5} the old current.

5 0
4 years ago
Which statements accurately describe the shape of Earth’s orbit around the Sun? Check all that apply.
damaskus [11]
<span>The Earth’s orbit is a nearly circular ellipse.
</span><span>The Sun is located at one of the two focal points.</span>

The Earth moves around the Sun in an orbit that is almost but not quite circular. As Kepler proved in the seventeenth century, the orbit is actually an ellipse. A parameter called the eccentricity (e) defines the degree of departure from a circle. A value of e=0 would indicate a circle whereas a value of e=0.9 would indicate a very elongated ellipse. The eccentricity of the Earth's orbit is currently e=0.0167.
4 0
3 years ago
Read 2 more answers
A bike is traveling to the left with the speed of 27 m/s when the rider slams on the brakes. The bike skids for 41.5 m with the
Darina [25.2K]

The acceleration of the bike is equal to 8.78\frac{m}{s^{2}} opposing the movement (to the right).

Why?

Since after the rider slams the brakes, the bike came to a stop, we know that the acceleration is opposite to the velocity/movement.

We can use the following equation to calculate the acceleration:

v_{f}^{2}=v_{o}^{2}+2*a*d

So, substituting, we have: (let's consider negative to the left and positive to the right)

0=(-27\frac{m}{s} )^{2}+2*a*41.5m\\\\0=729\frac{m^{2} }{s^{2} }+83*a\\\\a=\frac{-729\frac{m^{2}}{s^{2}}}{83m}=-8.78\frac{m}{s^{2}}

The negative sign means that the acceleration's direction is opposite to the movement.

Hence, we have that the acceleration is equal to 8.78\frac{m}{s^{2}} opposing the movement (to the right).

Have a nice day!

5 0
4 years ago
Read 2 more answers
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