Answer:
Part 1) Voltage in secondary windings is 61.08 Volts
Part 2) Current in secondary windings is 0.53 Amperes
Explanation:
The potential developed in the primary and secondary winding of a transformer are related as

where
Np no of turns in primary coil
Ns no of turns in secondary coil
Vp Voltage of turns in primary coil
Vs Voltage of turns in secondary coil
Applying values in the formula we get

Part 2)
Using Ohm's law the current is given by

0.4 N-s is the "impulse" acted on the "beach ball".
Option: C
Explanation:
Given that,
Mass of the "beach ball" is 0.1 kg.
The speed of the ball hits is 4 m/s.
We know that,
Whenever an object is collide with other object then an impulse is acted on object, this "impulse" causes "change in momentum".
Impulse acted on the beach ball is "mass" times "velocity".
Impulse = mass × velocity
Impulse = 0.1 × 4
Impulse = 0.4 kg m/s
Impulse = 0.4 N-s
Therefore, the "impulse" acted on the ball is 0.4 N-s.
Answer:
Explanation:
d = 42 meters
v = 12 m/s
t = ?
t = d/v
t = 42 / 12
t = 3.5 seconds. That's awfully fast.
Hope this provides some answers
Answer:
v_oy = 16.33 m/s
Explanation:
To find the vertical velocity of the tiger, you use the information about the horizontal velocity and maximum horizontal distance traveled.
You use the following formula for the range of the trajectory:
( 1 )
v_ox: horizontal initial velocity = 4.5m/s
v_oy: vertical initial velocity = ?
g: gravitational acceleration = 9.8m/s^2
x_max: range of the trajectory = 15 m
You do v_oy the subject of the formula ( 1 ) and you replace the values of the other parameters in order to calculate v_oy:

hence, the initial vertical velocity of the tiger is 16.33m/s