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Arte-miy333 [17]
3 years ago
7

To understand the vector nature of momentum in the case in which two objects collide and stick together. In this problem we will

consider a collision of two moving objects such that after the collision, the objects stick together and travel off as a single unit. The collision is therefore completely inelastic. You have probably learned that "momentum is conserved" in an inelastic collision. But how does this fact help you to solve collision problems?
Physics
2 answers:
ludmilkaskok [199]3 years ago
5 0

Answer:

Answer : The momentum is equal to the momentum of object 1 plus the momentum of object 2.

When masses collide with each other and stick together, the collision is said to be inelastic. The kinetic energy before collision and after collision are not equal. For the objects to stick together, they move in the same direction. Therefore the momentum is equal to the momentum of object 1 plus the momentum of object 2.

Explanation:

Plz give me brainliest

vlada-n [284]3 years ago
4 0

Answer:

Applying the law's theory and utilizing the equation of momentum ie. p=mv

Explanation:

The law of conservation of linear momentum states that the momentum in a <em>closed</em> system remains constant. Because a collision is inelastic, this proves that the system is closed. So the equation of momentum is p=mv, p is momentum, m is mass and v is velocity.

Because the momentum is conserved, the momentum (p) before the collision should be equal to the p after the collision, so we can equate them and solve for the unknown:

p=m.v

p(before) = p(after)

m(before) x v(before) = m(after) x v(after)

using this equation, you solve it and this helps you solve collision problems.

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A transformer consists of 290 primary windings and 824 secondary windings. Part A: If the potential difference across the primar
jasenka [17]

Answer:

Part 1) Voltage in secondary windings is 61.08 Volts

Part 2) Current in secondary windings is 0.53 Amperes

Explanation:

The potential developed in the primary and secondary winding of a transformer are related as

\frac{N_{p}}{N_{s}}=\frac{V_{p}}{V_{s}}

where

Np no of turns in primary coil

Ns no of turns in secondary coil

Vp Voltage of turns in primary coil

Vs Voltage of turns in secondary coil

Applying values in the formula we get

\frac{290}{824}=\frac{21.5}{V_{s}}\\\\\therefore V_{s}=21.5\times \frac{824}{290}=61.08V

Part 2)

Using Ohm's law the current is given by

I=\frac{V_{s}}{R}\\\\I=\frac{61.089}{115}=0.53A

5 0
3 years ago
A 0.1 kg beach ball hit me moving forward at 4 m/s. After hitting me, it bounced back moving at the same speed
xenn [34]

0.4 N-s is the "impulse" acted on the "beach ball".

Option: C

Explanation:

Given that,

Mass of the "beach ball" is 0.1 kg.

The speed of the ball hits is 4 m/s.

We know that,

Whenever an object is collide with other object then an impulse is acted on object, this "impulse" causes "change in momentum".

Impulse acted on the beach ball is "mass" times "velocity".

Impulse = mass × velocity

Impulse = 0.1 × 4

Impulse = 0.4 kg m/s

Impulse = 0.4 N-s

Therefore, the "impulse" acted on the ball is 0.4 N-s.

7 0
3 years ago
A shark travels with an average velocity of 12 m/s s. How long (time) would it take the shark to swim 42 m at that velocity
DerKrebs [107]

Answer:

Explanation:

d = 42 meters

v = 12 m/s

t = ?

t = d/v

t = 42 / 12

t = 3.5 seconds. That's awfully fast.

7 0
3 years ago
Solve the given parallel circuit by computing the desired quantities.
Alex Ar [27]

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7 0
3 years ago
A tiger leaps with a horizontal speed of 4.5 m/s from a boulder and lands 15 meters away.What is the vertical velocity with whic
Gelneren [198K]

Answer:

v_oy = 16.33 m/s

Explanation:

To find the vertical velocity of the tiger, you use the information about the horizontal velocity and maximum horizontal distance traveled.

You use the following formula for the range of the trajectory:

x_{max}=\frac{2v_{ox}v_{oy}}{g}     ( 1 )

v_ox: horizontal initial velocity = 4.5m/s

v_oy: vertical initial velocity = ?

g: gravitational acceleration = 9.8m/s^2

x_max: range of the trajectory = 15 m

You do v_oy the subject of the formula ( 1 ) and you replace the values of the other parameters in order to calculate v_oy:

v_{oy}=\frac{gx_{max}}{2v_{ox}}=\frac{(9.8m/s^2)(15m)}{2(4.5m/s)}\\\\v_{oy}=16.33\frac{m}{s}

hence, the initial vertical velocity of the tiger is 16.33m/s

8 0
3 years ago
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