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Reptile [31]
3 years ago
11

The probability that event A occurs is 57 and the probability that event B occurs is 23 . If A and B are independent events, wha

t is the probability that A and B both occur? Write your result in the empty box provided below in the simplest fraction form.
Mathematics
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

<h2>\frac{1}{1311}</h2>

Step-by-step explanation:

The probability of occurring the event A is \frac{1}{57}.

The probability to occur the event B is \frac{1}{23}.

It is also given that the events are independent that is they do not depends on each other.

So, the probability of occurring both the events simultaneously can be get by simply multiplying the probabilities of both the events.

Hence, the probability is \frac{1}{[tex]57times23}[/tex] = \frac{1}{1311}.

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Answer:

Incomplete problem - reword

Step-by-step explanation:

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2 years ago
If f(3) = 3(x+5+2, what is f(a+ 2)?
Mamont248 [21]

Solution:

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IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}

which would be

\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with 2^1=2 and ending with 2^6=64. So in sigma notation, this series is

\displaystyle\sum_{n=1}^6\frac1{2^n}

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madam [21]

Answer:

-2

Step-by-step explanation:

Hope this was helpful

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