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dybincka [34]
3 years ago
5

Write 3 580 569 in words.bought werere redmillionfi​

Mathematics
2 answers:
Trava [24]3 years ago
8 0
Three million, five hundred eighty thousand, five hundred sixty nine
kaheart [24]3 years ago
6 0

Answer:

Three million five hundred and eighty thousand five hundred and sixty nine.

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the administration of community hospital is studying the activity of their cardiovascular telemetry unit, which has 12 beds. dur
hoa [83]

The required  the average daily census for this period is 12.

<h3>What is Average?</h3>

A Average can be characterized as the amount of all numbers isolated by the all out number of values. A mean can be characterized as a normal of the arrangement of values in an example of information. At the end of the day, a normal is likewise called the math mean. It is known as a mean to Depict the average.

<h3 /><h3>According to question:</h3>

there were 2,200 inpatient service days.

Number of days between this period = 184 days

So, average daily census = 2200/184

11.95

⇒ 12 up to whole number.

To know more about average visit:

brainly.com/question/2906096

#SPJ4

6 0
1 year ago
What is y = -3(x – 7)(x + 3) in standard form?
xxTIMURxx [149]

Answer:

y=-3x^2+12x+63

Step-by-step explanation:

y=-3(x-7)(x+3)

y=-3(x^2-4x-21)

y=-3x^2+12x+63

4 0
3 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
2 years ago
Whoever gets this in 5 mins will be brainlest
ivanzaharov [21]

Answer:

easy its c

Step-by-step explanation:

so you do you start with the left 2 to the third power is 8

then the right side now is -3 to the second power is -9

in total 8- (9-)

so your answer is -1

hope this helps

8 0
2 years ago
Read 2 more answers
Please help me with my homework please answer this correctly
Ad libitum [116K]
The answer would be 200,000.
This is because you go to the hundred thousands' place and look one place to the right. Since there is a 6 and 6>5 you round up to 2 making it 200,000. Hope this helps!
5 0
2 years ago
Read 2 more answers
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