find the diameters of a circle with a circumference of 443 feet use 3.14 for n a. 70.5 b. 141 c.142 d.282

Mathematics

2 answers:

madreJ [45]2 years ago

8 0

The Answer Would Then Be Choice B. 141.

zvonat [6]2 years ago

3 0

The formula for diameter is:

circumference/pi (3.14)

If the circumference is 443, we can divide that by pi.

$443/3.14=141.01$

The answer would then be choice b (141).

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Justin owns a food truck that sells tacos and burritos. He only has enough supplies to

vfiekz [6]

Answer:

The solution in the attached figure

One possible solution is the point (30,60)

Step-by-step explanation:

Let

x -----> represents the number of tacos sold

y -----> represents the number of burritos sold

we know that

------> inequality A

-----> inequality B

using a graphing tool

The solution is the triangular shaded area

see the attached figure

One possible solution is the point (30,60)

Remember that if a ordered pair is a solution of the system of inequalities, then the ordered pair must lie on the shaded area of the solution

That means----> The number of tacos sold is 30 and the number of burritos sold

Verify

Substitute the value of x and the value of y in each inequality

Inequality A

----> is true

Inequality B

----> is true

The ordered pair satisfy both inequalities, then the ordered pair is a solution of the system

Read more on Brainly.com - brainly.com/question/13301815#readmore

Step-by-step explanation:

3 0

3 years ago

Suppose you are finding 296 divided by 4 using partial quotients. Is 50 or 70 a more reasonable partial quotient? Explain.

Lyrx [107]

Round 296 up to 300 and then divide 300 by 4 mentally. Answer: 75. Which is a more reasonable partial quotient, 50 or 70?

8 0

3 years ago

Factor:<br><br><br>(m+2)^2−(m+2)+mn·(n+2)+2n(n+2)

bazaltina [42]

ANSWER
${(m + 2)}( {n}^{2} + 2n + m + 1)$

EXPLANATION

The given expression is

${(m + 2)}^{2} - (m + 2) + mn(n + 2) + 2n(n + 2)$

We factor to get,

$= {(m + 2)}(m + 2 - 1) +n (n + 2) (m+ 2)$

This implies that,

$= {(m + 2)}(m + 1) +n (n + 2) (m+ 2)$

We factor further to obtain,

$= {(m + 2)}((m + 1) +n (n + 2))$

or

$= {(m + 2)}( {n}^{2} + 2n + m + 1)$