What is saturated solution and how it is prepared

Which segement of the heating curve shown above represents an increase in the potential energy, but no change in the kinetic ene

Ede4ka [16]

Answer: Option (b) is the correct answer.

Explanation:

Kinetic energy is defined as the energy obtained by the molecules of an object due to their motion.

Also, it is known that kinetic energy is directly proportional to temperature.

Mathematically, K.E = $\frac{3}{2}kT$

where, T = temperature

Whereas potential energy is defined as the energy obtained by an object due to its position.

Mathematically, P.E = mgh

where, m = mass

g = acceleration due to gravity

h = height

Therefore, in the given curve when temperature remains constant then kinetic energy of molecules will also remain.

Hence, we can conclude that the segment QR represents an increase in the potential energy, but no change in the kinetic energy.

7 0

3 years ago

_ Have both metallic and nonmetallic properties.

Ahat [919]

The answer is Metalloids!

6 0

2 years ago

Read 2 more answers

If 97.3 L of NO2 forms measured at 35 C and 632 mm Hg. What is the percent yield?

enyata [817]

a. Use PV = nRT and solve for n = number of mols O2.
mols NO = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR.

b.
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L.

and % will be 60%.

3 0

2 years ago

Help pleaseee

marissa [1.9K]

Answer:

In order to find the molecular formula from an empirical formula you must find the ratio of their molecular masses.

We know that the molecular mass of the molecule is 70

gmol-1

. We can calculate the molar mass of

CH2

from the periodic table:

C=12.01

gmol−1

H=1.01

gmol−1

CH2 =14.03

gmol−1

Hence we can find the ratio:

14.03

70

≈

0.2

6 0

3 years ago

agcl molar masA 250.0 g sample of a white solid is known to be a mixture of KNO3, BaCl2, and NaCl. When 100.0 g of this mixture

tatiyna

Answer:

a. BaSO₄ and AgCl.

b. 150.0g of BaCl₂, 50.0g of NaCl and 50.0g of KNO₃

Explanation:

Barium, Ba, from BaCl₂ reacts with the SO₄²⁻ of H₂SO₄ to produce BaSO₄, an insoluble white salt.

The reaction is:

BaCl₂ + H₂SO₄ → BaSO₄ + 2HCl

Also, Chlorides from BaCl₂ (2Cl⁻) and NaCl (1Cl⁻) react with AgNO₃ to produce AgCl, another white insoluble salt, thus:

Cl⁻ + AgNO₃ → AgCl + NO₃⁻

a. Thus, formulas of the two precipitates are: BaSO₄ and AgCl

b. Moles of BaSO₄ in 67.3g (Molar mass BaSO₄: 233.38g/mol) are:

67.3g × (1 mol / 233.38g) = 0.2884 moles of BaSO₄ = moles of BaCl₂ Because 1 mole of BaCl₂ produces 1 mole of BaSO₄

Now, as molar mass of BaCl₂ is 208.23g/mol, the mass of BaCl₂ in the mixture of 100.0g is:

0.2884 moles of BaCl₂ ₓ (208.23g /mol) = 60.0g of BaCl₂ in 100g of the mixture

Moles of the AgCl produced (Molar mass AgCl: 143.32g/mol) are:

197.96g ₓ (1mol / 143.32g) = 1.38 moles of AgCl.

As moles of Cl⁻ that comes from BaCl₂ are 0.2884 moles×2×1.5 (1.5 because the sample is 150.0g not 100.0g as in the initial reaction)

= 0.8652 moles of BaCl₂, that means moles of NaCl are:

1.38mol - 0.8652mol = 0.5148 moles of NaCl (Molar mass 58.44g/mol):

Mass NaCl in 150g =

0.5148mol NaCl × (58.44g/mol) = 30.0g of NaCl in 150.0g

That means, in the 250.0g of sample, the mass of BaCl₂ is:

60.0g BaCl₂ ₓ (250.0g / 100g) = 150.0g of BaCl₂

Mass of NaCl is:

30.0g NaCl ₓ (250.0g / 150g) = 50.0g of NaCl

As the total mass of the mixture is 250.0g, the another 50.0g must come from KNO₃, thus, there are 50.0g of KNO₃.

4 0

3 years ago