There are two N≡N bonds and three H–H bonds are in reactants.
Given:
The reaction between nitrogen gas and hydrogen gas.

To find:
Bonds on the reactant side
Solution:

Reactants in the reaction = 
The bond between nitrogen atoms in single
molecule = N≡N (triple bond)
Then in two
molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single
molecule = H-H (single bond)
Then in three
molecules = 3 H-H (single bonds)
Product in the reaction =
The bonds between nitrogen and hydrogen atoms in single
molecule = 3 N-H (single bond)
Then in two
molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
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I think the answer is:
B. Chemical Change.
Answer:
The change in entropy is -1083.112 joules per kilogram-Kelvin.
Explanation:
If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (
), in joules per gram-Kelvin, by the following model:

(1)
Where:
- Mass, in kilograms.
- Specific heat of water, in joules per kilogram-Kelvin.
,
- Initial and final temperatures of water, in Kelvin.
If we know that
,
,
and
, then the change in entropy for the entire process is:


The change in entropy is -1083.112 joules per kilogram-Kelvin.
It is a ,d and c just make sure tho