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svetlana [45]
3 years ago
12

Which elements would have properties similar to those of boron (B) ? Se , Li , and Be Al , Ga , and In C, N, and O Na , Mg , and

Al
Chemistry
1 answer:
n200080 [17]3 years ago
8 0

Answer:

option B= Al, Ga and In

Explanation:

Properties of Boron group:

  1. These elements are belongs to boron group which is thirteen group of periodic table. There are six elements are in this group boron, aluminium, gallium, indium, thallium and nihonium.
  2. They are also called p-block elements because their valance electrons are present in p subshell.
  3. All these elements have three valance electrons.
  4. Boron is metalloid while other elements are metals.
  5. Their oxidation state is +3 because of tendency to lose three valance electrons and create positive charge.
  6. Their atomic sizes increases down the group with increase of atomic number.
  7. Their ionization energies decreases down the group because of increase of atomic radius and ease of removing of electrons.

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Answer:

-43.3 °C

Explanation:

To find the temperature, you need to use the Ideal Gas Law equation. The equation looks like this:

PV = nRT

In this formula,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Law constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

By plugging the given values into the equation and simplifying, you can find the temperature. After you get a temperature, you need to convert it into Celsius.

P = 2.88 atm                              R = 0.08206 atm*L/mol*K

V = 3.76 L                                   T = ? K

n = 0.574 moles

PV = nRT

(2.88 atm)(3.76 L) = (0.574 moles)(0.08206 atm*L/mol*K)T

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For the aqueous reaction dihydroxyacetone phosphate is the reactant and glyceraldehyde 3 phosphate is the product. dihydroxyacet
lbvjy [14]

<u>Answer:</u> The Gibbs free energy of the reaction is -445 J/mol.

<u>Explanation:</u>

The chemical equation for the conversion follows:

\text{Dihydroxyacetone phosphate}\rightleftharpoons \text{Glyceraldehyde-3-phosphate}

The expression for K_{eq} of above equation is:

K_{eq}=\frac{\text{[Glyceraldehyde-3-phosphate]}}{\text{[Dihydroxyacetone phosphate]}}

We are given:

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\Delta G=\Delta G^o+RT\ln K_1

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\Delta G^o = Standard Gibbs free energy = 7.53 kJ/mol = 7530 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

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Putting values in above equation, we get:

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