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Svet_ta [14]
4 years ago
13

A 42.0 g sample of compound containing only C and H was analyzed. The results showed that the sample contained 36.0 g of Cand 6.

0 g of H. Which of the following questions about the
compound can be answered using the results of the analysis?
Chemistry
1 answer:
GREYUIT [131]4 years ago
7 0

Answer:

what are the following questions?

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What is closest packing? What is the difference between hexagonal closest packing and cubic closest packing? What is the unit ce
Paladinen [302]

Answer:

In crystal structure close packing is define as space efficient arrangement of constituent particles to form a crystal lattice.

Explanation:

closest packing

In crystal structure close packing is define as space efficient arrangement of constituent particles to form a crystal lattice.

Difference between hexagonal closest packing and cubic closest packing

In cubic closest packing arrangement, each sphere is surrounded by 12 other spheres on the other hand in case of hexagonal close packing, layers of spheres are packed so that spheres in alternating layers overlie one another.

unit cell for each closest packing arrangement

The hexagonal closest packed arrangement has a coordination number of 12 and it consists of 6 atoms per unit cell. The face centered cubic lattice has a coordination number of 12 and it consists of 4 atoms per unit cell. In case of body centered cubic crystal the coordination number is 8 and it consists of 2 atoms per unit cell.

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4 years ago
During which era did the supercontinent Pangaea break up?
Rudiy27
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3 years ago
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A bottle of 2 moles of an ideal diatomic gas experiences a temperature increase of 50.0K at constant volume. (a) Find the increa
andre [41]

Answer:

Explanation:

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5 0
3 years ago
Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +
qwelly [4]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) X(s)+\frac{1}{2}O_2(g)\rightarrow XO(s)    \Delta H_1=-668.5kJ

(2) XCO_3(s)\rightarrow XO(s)+CO_2     \Delta H_2=+384.3kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times \Delta H_1]+[1\times (-\Delta H_2)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-668.5))+(1\times (-384.3))=-1052.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

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