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4 years ago

13

A 42.0 g sample of compound containing only C and H was analyzed. The results showed that the sample contained 36.0 g of Cand 6.

0 g of H. Which of the following questions about the
compound can be answered using the results of the analysis?

1 answer:

GREYUIT [131]4 years ago

7 0

Answer:

what are the following questions?

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PLEASE HELP!!!!!!!!!

andreev551 [17]

The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

$\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu$

5 0

3 years ago

Compared with warm fronts cold fronts are?

liubo4ka [24]

A weather front or front is a narrow region between two air masses of different densities. Because of the difference in density between warm and cold front, cold air tends to go underneath the warmer air. It often creates the strongest winds above the ground surface. This is caused due to the heat and mass transfer between particles of air. They can be slowed down by the presence of mountains and valleys. Cold air moves fast and the temperature around it can be felt as if you are blown away due to its density. Whereas warm air moves slowly.

6 0

3 years ago

A student carried heated a 25.00 g piece of aluminum to a temperature of 100°C, and placed it in 100.00 g of water, initially at

lawyer [7]

<u>Answer:</u> The final temperature of the system is 14.60°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of aluminium = 25.00 g

$m_2$ = mass of water = 100 g

$T_{final}$ = final temperature = ?°C

$T_1$ = initial temperature of aluminium = 100°C

$T_2$ = initial temperature of water = 10°C

$c_1$ = specific heat of aluminium = 0.900 J/g°C

$c_2$ = specific heat of water= 4.18 J/g°C

Putting values in equation 1, we get:

$25\times 0.900\times (T_{final}-100)=-[100\times 4.18\times (T_{final}-10)]$

$T_{final}=14.60^oC$

Hence, the final temperature of the system is 14.60°C

3 0

3 years ago

How many moles are in 105.7 grams of aluminum

Inessa [10]

Answer:

3.918 mol Al

Explanation:

To convert between moles and grams, you have to use the molar mass of the substance. The molar mass of aluminum is 26.98 g/mol. You use this as the unit converter.

$105.7gAl *\frac{1molAl}{26.98gAl} =3.91771683molAl$

Round the number to the lowest number of significant figures; 3.918 mol Al

3 0

3 years ago

What is voltage? A. The pressure that pushes electrons to the anode; it is derived from the negative charge of electrons at the

Vlad [161]

Answer:

D

Explanation:

I think it's D but not 100% sure

4 0

3 years ago