To convert boiling water to steam, that would involve heat of vaporization. The heat of vaporization for water at atmospheric conditions is: ΔHvap = <span>2260 J/g.
Molar mass of water = 18 g/mol
Q = m</span>ΔHvap = (1.50 mol water)(18 g/mol)(<span>2260 J/g) = 61,020 J
Time = Q/Rate = (61,020 J)(1 s/20 J) = 3051 seconds
In order to express the answer in three significant units, let's convert that to minutes.
Time = 3051 s * 1min/30 s = <em>102 min</em></span>
Lithium-7 is the most common isotope of lithium.
Answer:
a )Li
b)O
c)F
Explanation:
a) Li-1s^2 2s^1
F-1s^2 2s^2 2p^5
it is easy to pull out e- from 2p orbit than 2s because 2s orbit is close to nucleus.Therefore Li have high ionisation enthalpy
b)oxygen ion is larger than Na because o have fewer proton
c)F because it requires only 1e to achieve stable noble gas configuration.Therefore to achieve stable nobke gas electonic configuration it accept 1e.
Answer: The initial temperature of the iron was ![515^0C](https://tex.z-dn.net/?f=515%5E0C)
Explanation:
![heat_{absorbed}=heat_{released}](https://tex.z-dn.net/?f=heat_%7Babsorbed%7D%3Dheat_%7Breleased%7D)
As we know that,
![Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})](https://tex.z-dn.net/?f=Q%3Dm%5Ctimes%20c%5Ctimes%20%5CDelta%20T%3Dm%5Ctimes%20c%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29)
.................(1)
where,
q = heat absorbed or released
= mass of iron = 360 g
= mass of water = 750 g
= final temperature = ![46.7^0C](https://tex.z-dn.net/?f=46.7%5E0C)
= temperature of iron = ?
= temperature of water = ![22.5^oC](https://tex.z-dn.net/?f=22.5%5EoC)
= specific heat of iron = ![0.450J/g^0C](https://tex.z-dn.net/?f=0.450J%2Fg%5E0C)
= specific heat of water= ![4.184J/g^0C](https://tex.z-dn.net/?f=4.184J%2Fg%5E0C)
Now put all the given values in equation (1), we get
![-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]](https://tex.z-dn.net/?f=-360%5Ctimes%200.450%5Ctimes%20%2846.7-x%29%3D%5B750%5Ctimes%204.184%5Ctimes%20%2846.7-22.5%29%5D)
![T_i=515^0C](https://tex.z-dn.net/?f=T_i%3D515%5E0C)
Therefore, the initial temperature of the iron was ![515^0C](https://tex.z-dn.net/?f=515%5E0C)