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4 years ago

Which matrix represents the solution to the system of equations below?

Mathematics

2 answers:

Helga [31]4 years ago

6 0

Answer:

The solution for this system is matrix A

Step-by-step explanation:

You can see step by step explanation in the attach.

First you have to identify the initial matrix looking at the coeficients. Once you do that, you proceed following rules to solve matrixs until obtaining the identity matrix. When you find this matrix, you find the solution for the system.

olga nikolaevna [1]4 years ago

3 0

Answer:

is C $\left[\begin{array}{ccc}2&1&1\\-1&1&-1\\1&-2&2\end{array}\right]$

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3 years ago

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telo118 [61]

Answer:

$\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Multiple Roots
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Algebra II

Imaginary Root i = √-1

Step-by-step explanation:

Step 1: Define

Identify

2x² + x + 67 = 0

a = 2

b = 1

c = 67

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}$
[√Radical] Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}$
[√Radical] Simplify: $\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

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3 years ago

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SashulF [63]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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6 0

3 years ago