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Karolina [17]
3 years ago
6

A triangle is rotated 90° about the origin. Which rule describes the transformation?

Mathematics
1 answer:
Kaylis [27]3 years ago
3 0
90 is almost 100 so ima go wid 2
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Choose the equation for the graph.
sesenic [268]

The correct equation of the given graph is; Option A: y = |x/2| - 5

<h3>How to find the equation of a graph?</h3>

From the given graph, we can see the following coordinates;

At x = 0, y = -5

At x = 1, y = -4.5

At x = -1, y = -4.5

At x = 2, y = -4

At x = -2, y = -4

Since the y-intercept is at y = -5, looking at the given options, the only one that is correct will be;

y = |x/2| - 5

Read more about equation of graph at; brainly.com/question/4025726

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5 0
2 years ago
Simplify -3/4 divided by 2/-8
kozerog [31]

Answer: 3

Step-by-step explanation:

(-3/4)/(-2/8)=(-3/4)(-8/2)=(-3/4)(-4)=3

3 0
4 years ago
Pls help i’m so dumb
Anna007 [38]

1. You got that one right ;)

2. 3(x+12)

3. c/3+10

4. 2+6x

5. 2/3x-11

6.  2(c-4)

7. 9x-7

8. 6x+7x

9. x+2x

10. 1/4x+11

4 0
3 years ago
Read 2 more answers
The shape of the distribution of the time required to get an oil change at a 15-minute oil-change facility is unknown. However,
horsena [70]

Answer:

The mean oil-change time that would there be a 10% chance of being at or below is 15.46 minutes.

Step-by-step explanation:

We are given that records indicate that the mean time is 16.2 minutes, and the standard deviation is 3.4 minutes.

On a typical​ Saturday, the​ oil-change facility will perform 35 oil changes between 10 A.M. and 12 P.M. Assuming that data follows normal distribution.

Let \bar X = <u><em>sample mean time</em></u>

The z score probability distribution for sample mean is given by;

                          Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 16.2 minutes

            \sigma = standard deviation = 3.4 minutes

            n = sample size = 35 oil changes

<u>Now, the mean oil-change time that would there be a 10% chance of being at or below is given by;</u>

<u></u>

          P(X \leq x) = 0.10          {where x is required mean oil-change time}

          P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{x-16.2}{\frac{3.4}{\sqrt{35} } } ) = 0.10

          P(Z \leq \frac{x-16.2}{\frac{3.4}{\sqrt{35} } } ) = 0.10

Now, in the z table the critical value of X which represents the below 10% of the probability area is given as -1.282, that means;

                  \frac{x-16.2}{\frac{3.4}{\sqrt{35} } }  =  -1.282

               x - 16.2  =  -1.282 \times {\frac{3.4}{\sqrt{35} } }

                         x  =  16.2 - 0.74 = <u>15.46 minutes</u>

Hence, the mean oil-change time that would there be a 10% chance of being at or below is 15.46 minutes.

8 0
3 years ago
Find the value of x. please help fast! i’ll give free thanks and mark brainlist! and points are 7
Vaselesa [24]

Answer:

it would be 18

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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