Answer:
0
Step-by-step explanation:
Find the following limit:
lim_(x->∞) 3^(-x) n
Applying the quotient rule, write lim_(x->∞) n 3^(-x) as (lim_(x->∞) n)/(lim_(x->∞) 3^x):
n/(lim_(x->∞) 3^x)
Using the fact that 3^x is a continuous function of x, write lim_(x->∞) 3^x as 3^(lim_(x->∞) x):
n/3^(lim_(x->∞) x)
lim_(x->∞) x = ∞:
n/3^∞
n/3^∞ = 0:
Answer: 0
Perhaps you meant <span>(a^3+14a^2+33a-20) / (a+4), for division by (a+4).
Do you know synthetic division? If so, that'd be a great way to accomplish this division. Assume that (a+4) is a factor of </span>a^3+14a^2+33a-20; then assume that -4 is the corresponding root of a^3+14a^2+33a-20.
Perform synth. div. If there is no remainder, then you'll know that (a+4) is a factor and will also have the quoitient.
-4 / 1 14 33 -20
___ -4_-40 28___________
1 10 -7 8
Here the remainder is not zero; it's 8. However, we now know that the quotient is 1a^2 + 10a - 7 with a remainder of 8.
<em>Complete Question:</em>
<em>You plant an 8-inch spruce tree that grows 4 inches per year and a 14-inch hemlock tree that grows 6 inches per year. </em>
<em>The initial heights are shown. </em>
Write a system of linear equations that represents this situation.
Answer:
Step-by-step explanation:
Given
Spruce Tree (s):
(yearly)
Hemlock Tree (h):
(yearly)
Required
Represent as system of linear equations
Let the number of years be x.
In both cases, the equation can be formed using:
For Spruce Tree (s):
For Hemlock Tree (h):
<em>Hence, the equations are </em><em> and </em><em></em>
