A minor league plays 101 games,
They win 14 more than twice as many as they lost.
How many wins and loses?
Okay, simple.
First, write a simple addition equation. In this case wins = w and losses = l.
l + w = 101.
Now, we have to figure out a way to make one of the terms the same term as the other, in this case we can change the terms of w to l.
l = l
w = 2l +14 (14 more than twice the amount)
Okay. So plug in the new amount for w.
l + 2l + 14 = 101. Great! we now have a simple equation. lets solve.
put similar terms together.
3l + 14 = 101
3l = 87
l = 29
So, we have 29 loses, and
w = 2(29) + 14
72 wins!
To check,
72 + 29 = 101, correct!
Hope this helps!
Answer:
A and B
Step-by-step explanation:
Now, look at your answer choices, which options are less than or equal to -2?
x ≤ -2, Check your answers:
A. -3 ≤ -2?
This statement is correct (-3 is < -2)
B. -2 ≤ -2 <== our original answer
This statement is correct (-2 is = to -2)
C. -1 ≤ -2
This statement is incorrect (-1 is > -2, not ≤ -2)
D. 0 ≤ -2
This statement is incorrect (0 is > -2, not ≤ -2)
E. 1 < -2
This statement is incorrect (1 is > -2, not ≤ -2)
Therefore, the correct options are A and B
Hope this helps!
Answer:
Results:
0.1432
0.0045
0.0905
0.0483
Step-by-step explanation:
Step a:
P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432
Step b:
P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045
Step c:
P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905
Step d:
P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483
As well we get the probability by subtracting a, b and c:
P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482
Answer:
(4, 2.5)
Step-by-step explanation:
