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Sveta_85 [38]
3 years ago
12

In golf your scores can be under or over par. If a golfer has 3 games in which he scores 3 under on the first, 5 over in the sec

ond and 3 under on the third, what is his total score after the three games?
Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0
(-3)+(5)+(-3)=-1
The awnser is -1.
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Which of the following are valid names for the triangle below? Check all that apply.
Sholpan [36]

Answer:

the answer i think is DMR

Step-by-step explanation:

because u use the letters from the corners

3 0
3 years ago
What is the simplest form of 145 over 261
-Dominant- [34]
The simplest form of 145/261 is 5/9
7 0
3 years ago
Read 2 more answers
How do I work this out???
Finger [1]
Okay so form a right angle triangle and the angle of that is 65 as it is right angle so 90 - 25= 65. label the sides like the pic below. 

we have the hypothenuse as well as the angle and we are trying to find the o(opposite side) 

o/h =sin
sin 65=23/h
sin 65 = 23/x
23/sin 65=x 
x=25.4
how high the kite is above ground is :
= 25.4 +1.2
 =26.6

7 0
3 years ago
Triangle ΔABC has side lengths of a = 18, <img src="https://tex.z-dn.net/?f=b%3D18%5Csqrt%7B3%7D" id="TexFormula1" title="b=18\s
ozzi

The measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

<h3 /><h3>What is the law of cosine?</h3>

When the three sides of a triangle is known, then to find any angle, the law of cosine is used.

It can be given as,

\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle B=\cos^{-1}\left(\dfrac{a^2+c^2-b^2}{2ac}\right) \\\angle C=\cos^{-1}\left(\dfrac{a^2+b^2-c^2}{2ab}\right)

Here, a,b and c are the sides of the triangle and A,B and C are the angles of the triangle.

Triangle ΔABC has side lengths of a = 18, b=18√3  and c = 36 inches.

  • Part A: Determine the measure of angle A

Put the value, in the cosine law, the measure of angle A.

\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle A=\cos^{-1}\left(\dfrac{(18\sqrt{3})^2+36^2-18^2}{2(18\sqrt{3})(36)}\right) \\\angle A=0.5236\rm\; rad\\\angle A=30^o\rm\; degree\\

  • Part B: Show how to use the unit circle to find tan A

Using the chart of unit circle, the value of tangent A can be found out. The tangent A is,

\tan A=\tan 30^o\\\tan A=\dfrac{1}{\sqrt{3}}

  • Part C: Calculate the area of ΔABC.

Use the following formula to find area of ΔABC.,

A=\dfrac{ab.\sin C}{2}\\A=\dfrac{18\times18\sqrt{3}.\sin C}{2}\\A=280.6\rm\; in^2

Thus, the measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

Learn more about the law of cosine here;

brainly.com/question/4372174

#SPJ1

7 0
2 years ago
0.92 is 10 times as much as
jeyben [28]
Well just divide and .92 divided by 10 = .092 because you move the value place. so the tenths go to the hundredths and get .092. .092 is the answer
5 0
3 years ago
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