5. For the data in the table below, find the sum of the absolute deviations for the predicted values

Mathematics

1 answer:

Kipish [7]2 years ago

4 0

Based on the absolute deviations and the predicted values, the sum of absolute deviations will be 4.8.

<h3>What would be the sum of absolute deviations from predicted values?</h3>

This can be found as:

= ∑ (Observed value - Predicted value)

The observed values are given in the table and the predicted values will be calculated using y = 3.6x - 0.4.

Solving gives:

= [3 - (3.6 x 1 - 0.4)] + [7 - (3.6 x 2 - 0.4)] + [ 9 - (3.6 x 3 - 0.4)] + [14 - (3.6 x 4 - 0.4)] + [15 - (3.6 x 5 - 0.4)] + [21 - (3.6 x 6 - 0.4)] + [25 - (3.6 x 7 - 0.4)]

= 0.2 + 0.2 + 1.4 + 0 + 2.6 + 0.2 + 0.2

= 4.8

Find out more on absolute deviation at brainly.com/question/447169.

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What is -1/3+w=5 3/8 express in simplest form

Elodia [21]

Let's solve your equation step-by-step.
 $\frac{-1}{3}$ +w=5 $\frac{3}{8}$ 
Step 1: Simplify both sides of the equation.
w+ $\frac{-1}{3}$ = $\frac{43}{8}$ 
Step 2: Add $\frac{1}{3}$ to both sides.
w+ $\frac{-1}{3}$ + $\frac{1}{3}$ = $\frac{43}{8}$ + $\frac{1}{3}$ 
w= $\frac{137}{24}$ 

Answer:w=5 $\frac{17}{24}$