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yuradex [85]
3 years ago
10

How do you do this question?

Mathematics
1 answer:
klio [65]3 years ago
5 0

Answer:

positive

Step-by-step explanation:

Find the sign of (2-2x+y) for any point (x,y) in quadrant 2.

In quadrant 2, the x's are negative and the y's are positive.

So choose a negative value for x and a positive value for y and evaluate:

2-2x+y

Let's try (-4,5):

2-2(-4)+5

2+8+5

15 (positive)

Let's try(-1/2 , 10):

2-2(-1/2)+10

2+1+10

3+10

13 (positive)

Let's try in general Let (x,y)=(-a,b) where a and b are positive:

2-2(-a)+b

2+2a+b

Since a and b are positive, then 2+2a+b is positive because you are adding three different positive numbers.

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How to find the measure of 2 supplementary angles if the differences in the measures of the angles is 102 degrees?
uysha [10]
You would do 180 - 102 to find the answer
7 0
3 years ago
What is the value of x in the right triangle below? Show your work and round your answer to the nearest hundredth. ​
navik [9.2K]

The length of the hypothenuse or the value of x is equal to 19.53

Data;

  • hypothenuse = x
  • adjacent = 11.2
  • opposite = 16
<h3>Pythagoras's Theorem</h3>

To solve this problem, we have to use Pythagoras's theorem which is used to find the missing side in a right angle triangle if we have at least two sides.

The formula for this is

x^2 = y^2 + z^2\\

Let's substitute the values and solve for the missing side

x^2 = 16^2 + 11.2^2 \\x^2 = 256 + 125.44\\x^2 = 381.44\\x = \sqrt{381.44} \\x = 19.53

The length of the hypothenuse or the value of x is equal to 19.53

Learn more Pythagoras theorem here;

brainly.com/question/3317136

6 0
3 years ago
Who could help me solve this
Monica [59]
6561 hope this helps 
6 0
3 years ago
Read 2 more answers
Multiple choice please help
Yuri [45]
C, adding the rest of this sentence because it needs to be longer
6 0
3 years ago
Help me with this one please​
lesya [120]
For me, it’s easiest when i distribute the negative sign if i need to and then reorder to put the like terms together. and then solve.
(also sorry if it’s a little confusing with all the parentheses, i use them because it helps me organize everything)


21. (4x-9y) + (6x+10) + (8y-4)
= 4x + 6x - 9y + 8y + 10 - 4
= 10x - y + 6
—> D

22. (6x+9y-15) + (2x-9y+8)
= 6x + 2x + 9y - 9y - 15 + 8 (the 9y - 9y = 0, so you can leave it out of the final equation)
= 8x - 7
—> D

23. (9x^2-8x+3) - (5x^2-6x+4)
= 9x^2 - 8x + 3 - 5x^2 -(-6x) - 4
= 9x^2 - 5x^2 - 8x + 6x + 3 - 4 (remember that two - signs next to each other make a + sign)
= 4x^2 - 2x - 1
—> A

24. (9x^3-7x+8) - (5x^2+7x-10)
= 9x^3 - 7x + 8 - 5x^2 - 7x -(-10)
= 9x^3 - 5x^2 - 7x - 7x + 8 + 10
= 9x^3 - 5x^2 - 14x + 18
—> D

25. (6x+14y) - ((7x+5y) + (x-8y))
= (6x+14y) - (7x + x + 5y - 8y)
= (6x+14y) - (8x-3y)
= 6x + 14y - 8x -(-3y)
= 6x - 8x + 14y + 3y
= -2x + 17y
—> B
5 0
2 years ago
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