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yuradex [85]
3 years ago
10

How do you do this question?

Mathematics
1 answer:
klio [65]3 years ago
5 0

Answer:

positive

Step-by-step explanation:

Find the sign of (2-2x+y) for any point (x,y) in quadrant 2.

In quadrant 2, the x's are negative and the y's are positive.

So choose a negative value for x and a positive value for y and evaluate:

2-2x+y

Let's try (-4,5):

2-2(-4)+5

2+8+5

15 (positive)

Let's try(-1/2 , 10):

2-2(-1/2)+10

2+1+10

3+10

13 (positive)

Let's try in general Let (x,y)=(-a,b) where a and b are positive:

2-2(-a)+b

2+2a+b

Since a and b are positive, then 2+2a+b is positive because you are adding three different positive numbers.

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What belongs in the box marked with the question mark in the proof?
koban [17]
<span>the blank boxes are for you to plug in x=20 to prove its right. so it would be 3(20)-4=2(20+8) 60-4=2(28) 56=56 so its true!</span>
6 0
3 years ago
What is the approximate perimeter of a semicircle with a radius of 9mm?
Cerrena [4.2K]
Act like it's a whole circle and find the perimeter, then divide by 2.

P = 2 * pi * r

P = 2 * 3.14 * 9

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Now divide by 2:

P = 28.26
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3 years ago
Read 2 more answers
What is X?<br> x-3.9=12.4
valentinak56 [21]

Answer:

Its 8.5

Step-by-step explanation:

I calculator

12.4+-3.9=8.5

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3 years ago
Find the length of the third side. If necessary, round to the nearest tenth.<br> 30<br> 18
grigory [225]

Answer:

24

Step-by-step explanation:

use Pythagoras theorem

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18^2+b^2=30^2

b^2 = 30^2 - 18^2

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8 0
2 years ago
What is the quadratic domain of y=x squared
statuscvo [17]

domain is the numbes you are allowed to use for x

what I usually do is just find the numbers that aren't allowed in the domain. such numbers are numbers that cause a division by 0 or a squaer root of a negative number

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so domain is all real numbers or D={x | -∞<x<∞}

4 0
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