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timama [110]
3 years ago
6

What is the perimeter of the figure shown below?

Mathematics
1 answer:
ra1l [238]3 years ago
4 0
The perimeter is the sum of all of the sides.

3x + 2 + x + 13 + 3x + 8 + 2 + x + 5

Combine like terms:

8x + 30

So the perimeter is 8x + 30
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4 years ago
Figure ABCD is a parallelogram<br><br> What are the lengths of line segments AB and BC?
Olegator [25]

Question is Incomplete,Complete question is given below;

Figure ABCD is a parallelogram.

What are the lengths of line segments AB and BC?

AB = 4; BC = 16

AB = 4; BC = 8

AB = 10; BC = 20

AB = 10; BC = 28

Answer:

AB = 10 ;BC =28.

Step-by-step explanation:

The Diagram is missing in the question we have attached the diagram for your reference.

Given:

AB = 3y -2

DC = y+6

BC = x+12

AD = 2x-4

We need to find the lengths of AB and BC.

Solution:

Since given that Figure ABCD is a parallelogram.

"The opposite side of parallelogram are equal."

Hence we can say that;

AB = DC

Substituting the value we get;

3y-2=y+6

Combining the like terms we get;

3y-y=6+2\\\\2y =8

Dividing both side by 2 we get;

\frac{2y}{2}=\frac{8}{2}  \\\\y=4

Now AB = 3y -2 =3\times 4-2 =12-2 =10

Also

BC = AD

Substituting the value we get;

x+12=2x-4

Combining the like terms we get;

2x-x=12+4\\\\x =16

Now BC = x+12 =16+12 =28

Hence AB = 10 and BC =28.

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