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tatyana61 [14]
3 years ago
12

An optimal solution to a linear programming problem MUST lie A. somewere on the line between two corner points. B. somewhere out

side of the feasible region. C. somewhere in the interior of the feasible region. D. at the intersection of at least two constraints.
Computers and Technology
1 answer:
g100num [7]3 years ago
8 0

Answer:

D. at the intersection of at least two constraints.

Explanation:

Linear programming is an optimization technique which is fine for the purpose of getting the best solution such as maximizing profit or certain o 4th era quantities. It is fine by modelling real life problems into mathematical models that have linear relationships or constraints such as in the form of objective functions. In linear programming, an objective function defines the formula for quantity optimization and the goal from this is to determine variable values that maximize or minimize the objective function depending on the problem robbery solved.

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The scene of a human sitting at a computer terminal, responding to stimuli flashed on the computer screen, would most likely be
katrin2010 [14]

I guess the correct answer is information processing

Infοrmatiοn prοcеssing is thе changе (prοcеssing) οf infοrmatiοn in any mannеr dеtеctablе by an οbsеrvеr. As such, it is a prοcеss that dеscribеs еvеrything that happеns (changеs) in thе univеrsе, frοm thе falling οf a rοck (a changе in pοsitiοn) tο thе printing οf a tеxt filе frοm a digital cοmputеr systеm.

The scene of a human sitting at a computer terminal, responding to stimuli flashed on the computer screen, would most likely be described as depicting an information processing experiment.

7 0
2 years ago
Given the lists list1 and list2, not necessarily of the same length, create a new list consisting of alternating elements of lis
tester [92]

Answer:

The following code is written in Python Programming Language.

Program:

list1=[1,2,3]

 # initialized the list type variable

list2=[4,5,6,7,8]

  # initialized the list type variable

list3=[]

   # initialized the empty list type variable

for j in range(max(len(list1), len(list2))):   #set for loop

 if j<len(list1):

  #set if statement

   list3.append(list1[j])

  #value of list1 appends in list3  

 if j<len(list2):

   #set if statement

   list3.append(list2[j])

  #value of list2 append in list3

print(list3)    #print the list of list3

Output:

[1, 4, 2, 5, 3, 6, 7, 8]

Explanation:

Here, we define three list type variables "list1", "list2", "list3" and we assign value in only first two variables "list1" to [1, 2, 3] and "list2" to [4, 5, 6, 7, 8] and third list is empty.

Then, we set the for loop and pass the condition inside it we pass two if conditions, in first one we compare the list1 from variable "j" inside it the value in list1 will append in list3, and in second one we compare "j" with list two and follow the same process.

After all, we print the list of the variable "list3".

5 0
3 years ago
A(n) ____________ specifies a variable's name and data type.
Alla [95]
I think that would be a function
4 0
3 years ago
Read 2 more answers
What action requires a UV map?
CaHeK987 [17]
I would say drawing a polygon for a new model, assuming that the polygon would be converted to 3D to create the model.

(I really hope this helps)
5 0
2 years ago
Read the code below.
Rasek [7]

Answer:

theres an error on line one used python idle

Explanation:

8 0
3 years ago
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