Graph the inequality:Y>-x+3I would very much appreciate the help :)
1 answer:
Answer:
See attached picture.
Step-by-step explanation:
To graph the inequality, use the y = mx + b form for linear equations. Here y > -x + 3 has slope of -1 and y-intercept of 3. Plot a point at (0,3) and move down 1 unit and 1 unit to the right. Plot a new point at (1,2). Connect the points with a dashed line. A dashed line is used for all inequalities which are not equal to. Finally, shade one side of the line. To determine which side, test a point not on the line. Shade the side which makes the inequality true.
y > -x + 3 test (0,0)
0 > -0 + 3
0 > 3 is false
Shade the side that does not have (0,0).
You might be interested in
Answer:
Step-by-step explanation:
The question is as following:
The verticies of a triangle on the coordinate plane are
A(0, 0), B(2, 0) and C(0, 2).
What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?
=============================================
Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).
IF the triangle is dilated by a factor of k about the origin, then
(x,y) → (kx , ky)
that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.
It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.
If a figure dilated by a factor of 1/3 about the origin
So,
<u>So, The coordinates of the triangle A'B'C' are:</u>