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3 years ago

9

After a concert for 1600 people, only eight people said they would not go to see the band again what percentage of the people wh

o went to the concert said they would not go to see the band again

1 answer:

Art [367]3 years ago

7 0

Answer:

0.5%

Step-by-step explanation:

That percentage would be:

8 people

--------------------- = (1/200) = 0.005 multiplied by 100% yields 0.5%

1600 people

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The function f(x) = –x2 + 20x – 75 models the profit from one customer, in dollars, a shop makes for printing photos, where x is

trasher [3.6K]

The function is graphed as shown below

Part A:

We use the formula $- \frac{b}{2a}$ to find the vertex of the function. A quadratic function of the form of $a x^{2} +bx+c$ and equating this form to the given function $- x^{2} +20x-75$ , we have
$b=20$ and $a=-1$ .

Substituting $a$ and $b$ into the vertex formula, we have
$x=- \frac{20}{2(-1)}=10$ , as shown in the graph

This calculation means that the highest profit is achieved when the number of photo printed equals to ten photos

Part B:

We can find solution to this equation by factorising

$- x^{2} +20x-75=0$
$-( x^{2} -20x+75)=0$
$x^{2} -20x+75=0$
$(x-5)(x-15)=0$
$x=5$ and $x=15$ , as shown in the graph

The two values means that the company makes no profit when they either produce 5 or 15 photos

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The scatter plot shows a correlation between the years and the rainfall in centimeters in Tennessee.

nataly862011 [7]

Answer:

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Step-by-step explanation:

The <u>actual values</u> are shown on the given graph as <u>blue points</u>.

The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.

From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.

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<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.

From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.

⇒ Difference = 44 - 40 = 4 cm

<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>

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