The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)
<em><u>Solution:</u></em>
Given that,
<em><u>We have to substitute eqn 1 in eqn 2</u></em>
Substitute x = 2.1925 in eqn 1
y = 2.1925 + 3
y = 5.1925
Substitute x = -3.1925 in eqn 1
y = -3.1925 + 3
y = -0.1925
Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)
Answer:
The probability is 1/28,561
Step-by-step explanation:
Here, we want to find the probability that each of the players will receive exactly one ace.
In a deck of cards, we have 4 suites of 13 cards each, with each of the suites consisting of 1 ace.
So, the probability of getting an ace for each of the four players will be 4/52 = 1/13
Now, the probability of each of the players getting exactly one ace will be; first got one ace , second got one , third got one and fourth got one.
mathematically, this probability will be 1/13 * 1/13 * 1/13 * 1/13 = (1/13)^4 = 1/28,561
Answer:
Domain -5 ≤x<1
Range -4 ≤y<7
Step-by-step explanation:
The domain is the values that x takes
X goes from -5 included to 1 not included
-5 ≤x<1
The range is the values that y takes
y goes from -4 included to 7 not included
-4 ≤y<7
