Answer:
$500
Step-by-step explanatioThe numberber of years driven is the first and second year
= 2
Miles driven
First year= 15,500
Second year= 14,500
Therefore the cost of depreciation can be calculated as follows
15,500-14,500/2
= 1000/2
= 500
Hence the cost of depreciation is $500
Answer:
H₀: μ ≤ μ H₁: μ > μ
Step-by-step explanation:
Hello!
If battery 1 lasts longer than battery 2, and all the batteries of population 1 and population 2 are built using the same method, then you could say that the population mean of the lifespans of batteries 1 are longer than the lifespan of batteries 2. Symbolically: μ₁ > μ₂
This would be your alternative hypothesis.
The null hypothesis is:
H₀: μ₁ ≤ μ₂
Then the correct answer is number 5
Looked for exercise's Options
H₀: μ ≥ μ H₁: μ < μ
H₀: μ ≤ -μ H₁: μ > -μ
H₀: μ ≥ -μ H₁: μ < -μ
H₀: μ = μ H₁: μ ≠ μ
H₀: μ ≤ μ H₁: μ > μ
