Solution:
y = 2x^2 - 3 ---- equation 1
y = 3x - 1 ------equation 2
Then we get,
2x^2 - 3 = 3x - 1
Now, simplifying the equation, we get
2x^2 - 3x - 3 + 1 = 0
2x^2 - 3x - 2 = 0
After factoring the equation, we get
(2x+1)(x-2) = 0
So, this means
(2x+1) = 0 and (x-2) = 0
From this, we get
x = -1/2 and x = 2
Putting values of x = -1/2 in equation 2
y = 3(-1/2) - 1
y = -2.5
Now, putting value of x = 2 in equation 2
y = 3(2) -1
y = 5
Answer: number one is 24
Step-by-step explanation: all you have to do is just minus i’m pretty sure and for the negative ones add the negative number and the other number together. If they are both negative then just act like the negative sign is not there and add the sign back after you find the distance
Supplementary means they are equal to 180 so combine them and set it equal to 180.
7x - 2 = 180
Add 2
7x = 182
Divide by 7
x = 26
Since it's either/or, we can simply add up 3/10 (0.3) and 1/5 (0.2) to get 0.5=1/2