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3 years ago

HOW can a table be used to find the rate of change and the initial value?

1 answer:

4 0

The data will display the data. When you look at the data and see the change in the data, that is how you can see what is the rate of change. You find the initial volume by using the data from the chart as if you was just reading the biggest of all the value.

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If the Cost price of the an article is greater than the selling price, we have a ____?

Olegator [25]

Answer:

loss

Step-by-step explanation:

Selling an item for less than was paid gives a loss

Selling an item for more than was paid gives a profit

4 0

3 years ago

Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin

saw5 [17]

Treat $\mathcal C$ as the boundary of the region $\mathcal S$ , where $\mathcal S$ is the part of the surface $z=2xy$ bounded by $\mathcal C$ . We write

$\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r$

with $\mathbf f=(y+7\sin x,z^2+9\cos y,x^3)$ .

By Stoke's theorem, the line integral is equivalent to the surface integral over $\mathcal S$ of the curl of $\mathbf f$ . We have

$\nabla\times\mathbf f=(-2z,-3x^2,-1)$

so the line integral is equivalent to

$\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$
$=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

where $\mathbf s(u,v)$ is a vector-valued function that parameterizes $\mathcal S$ . In this case, we can take

$\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)$

with $0\le u\le1$ and $0\le v\le2\pi$ . Then

$\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$

and the integral becomes

$\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$
$=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi$

4 0

3 years ago

Can someone please help me out? It would really make me happier if you did.

asambeis [7]

Answer:

B) 8 and 24.

Step-by-step explanation:

Just by looking at the answer choices, since one number must be three times the other, we can determine that the correct answer is B.

Regardless, let's work this out mathematically. Let the first number be a and the second number be b.

Their difference is 16. Hence:

$a-b=16$

The first number is three times the second number. So:

$a=3b$

Substitute:

$3b-b=16$

Solve for b. Subtract:

$2b=16$

And divide both sides by two:

$b=8$

So, the second number is 8.

And since the first number is three times the second, the first number is 24.

Our answer is B as expected.

5 0

3 years ago

How do you graph y=2x-10

bixtya [17]

One of the easier approaches would be that of x- and y-intercepts.

Setting x=0 results in y=-10; the y-intercept is (0, -10).
Setting y = 0 results in x = 5, so the x-intercept is (5,0).

Plot these 2 points. Then draw a str. line thru these points.

6 0

3 years ago

Your favorite activity outside of school is?

densk [106]

Answer:

Well, I play guitar as a hobby, and I play soccer for fun.

-BBBM

4 0

3 years ago

Read 2 more answers