Answer:
holy.... that's a lot of variables.
4t+2s+w+u+x+v
Answer:
A. square root of a^2 + b^2 for both answers
Step-by-step explanation:
The first problem, we are given
a^2 + b^2 = c^2
What we do is solve for c.
sqrt(a^2 + b^2) = c
c = sqrt(a^2 + b^2)
For problem 2,
WE can apply the Pythagorean theorem because we have a right triangle.
The equations is
a^2 + b^2 = c^2 like the first problem
Solving gets us
sqrt(a^2 + b^2) = c
c = sqrt(a^2 + b^2)
9514 1404 393
Answer:
(-5,1)
Step-by-step explanation:
To eliminate x, multiply the first equation by 3 and add 2 times the second equation.
3(-2x +7y) +2(3x -4y) = 3(17) +2(-19)
-6x +21y +6x -8y = 51 -38
13y = 13
y = 1 . . . . . matches the third answer choice
(x, y) = (-5, 1)
Pemdas, so exponent before multiply
so do a^-1/2 then multiply it by 2
remember that
![x^ \frac{m}{n}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
and

therefor,

the we multiply by 2
Answer:
Adding by 4 each time
Step-by-step explanation: