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3 years ago

Will you check my math its supposed to be a face!

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

6 0

It looks like a face to me

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HURRRYYYYY PLEASEEEEE

zepelin [54]

Answer:

I believe it's 12.

Step-by-step explanation:

The interquartile is the box I think.

7 0

3 years ago

Find an m > 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.

Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

$x^4-(3m+2)x^2+m^2=0$

$x^4+0x^3-(3m+2)x^2+0x+m^2=0$

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

$a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}$

$=\frac{0}{1}=0$

$\implies a=0----(1)$

$(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}$

$=\frac{-3m-2}{1}$

$3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2$

$-10b^2=-3m-2$

$\implies b^2=\frac{3m+2}{10}-----(2)$

$(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2$

$9b^4=m^2$

$9(\frac{3m+2}{10})^2=m^2$

$9(\frac{9m^2+4+12m}{100})=m^2$

$81m^2+36+108m=100m^2$

$-19m^2+108m+36=0$

$19m^2-108m-36=0$

$19m^2-114m+6m-36=0$

$19m(m-6)+6(m-6)=0$

$(19m+6)(m-6)=0$

$\implies m=-\frac{6}{19}\text{ or }m=6$

But m > 0,

Hence, the value of m is 6.

4 0

3 years ago

Find the sum of QR<br> 4x+33

12345 [234]

Answer:

Step-by-step explanation:

Simplifying

4x + 5 = 33

Reorder the terms:

5 + 4x = 33

Solving

5 + 4x = 33

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.

5 + -5 + 4x = 33 + -5

Combine like terms: 5 + -5 = 0

0 + 4x = 33 + -5

4x = 33 + -5

Combine like terms: 33 + -5 = 28

4x = 28

Divide each side by '4'.

x = 7

Simplifying

x = 7

4 0

2 years ago

Q bisects PR, PQ=3y, and PR=42. Find y and QR.

Vedmedyk [2.9K]

|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|

|PQ| = 3y; |PR| = 42; |QR|=?

subtitute

42 = 2(3y)
6y = 42 |divide both sides by 6
y = 7

|QR| = 3(7) = 21

3 0

3 years ago

The perimeter of the cover of a math textbook is 34 inches. If the width of the cover is 7 inches, what is the length of the cov

Ierofanga [76]

A= lxw = 34 Times 7 meaning the answer is 238

6 0

3 years ago

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