In rhombus ABCD, the diagonal line AC and line BD intersect at E. If AE=5 and BE = 12, what is the length of line AB?
1 answer:
From a formula located here:
http://www.1728.org/quadltrl.htm
we see that
<span>4 • Side² = Long Diagonal² + Short Diagonal²
Long Diagonal = 24
Short Diagonal = 10
</span><span>4 • Side² = 24^2 + 10^2 </span>
<span>4 • Side² = 576 + 100
</span><span>4 • Side² = 676
</span><span><span>Side²</span> = 169
Side (or line AB) = 13
</span>
http://www.1728.org/quadltrl.htm
we see that
<span>4 • Side² = Long Diagonal² + Short Diagonal²
Long Diagonal = 24
Short Diagonal = 10
</span><span>4 • Side² = 24^2 + 10^2 </span>
<span>4 • Side² = 576 + 100
</span><span>4 • Side² = 676
</span><span><span>Side²</span> = 169
Side (or line AB) = 13
</span>
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Answer:
x = a/(a² + b²) or x = -1/a
Step-by-step explanation:
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Use the quadratic equation formula:
1. Evaluate the discriminant D
D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b² = (b² + 2a²)²
2. Solve for x