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pogonyaev
3 years ago
6

A basketball diamond is actually a square with sides of 90 feet. If a runner tries to steal second base, how far must the catche

r, at home plate, throw to get the runner "out"?
Mathematics
1 answer:
Tpy6a [65]3 years ago
4 0

Answer:

127.28 feet

Step-by-step explanation:

Given

Shape of basketball diamond = Square

Length of a side = 90 feet

If the length of a side is 90 feet then the length of other sides is 90 feet.

By finding how far the catcher, at home plate, throw to get the runner "out", we are basically finding the distance from 2nd base to home

This means we're calculating the diagonal of the field..

(Since the field is a square, it has a right angle at 1st base)

Let the diagonal be representing by x.

From Pythagoras,

x² = 90² + 90²

x² = 8100 + 8100

x² = 16200

x = √16200

x = 127.2792206135785

x = 127.28 feet ------ Approximated

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alexgriva [62]

A ≈ 473.63

Step-by-step explanation: To find the surface area for a pyramid, we can use this formula: A=lw+l\sqrt{(\frac{w}{2})^2 } +h^2+w\sqrt{(\frac{l}{y} } )^2+h^2

Solution: 10\times10+10\times\sqrt{(\frac{10}{2} } )^2+18^2+10\times\sqrt{(\frac{10}{2} } )^2+18^2=423.63

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7 0
3 years ago
Please help urgent!!
trapecia [35]

Answer:

<em>The area of the rectangle is</em> A=12b^6+6b^3-18b^2

Step-by-step explanation:

<u>Area of a rectangle</u>

A rectangle of height H and width W has an area of:

A=H*W

The rectangle shown in the figure has a height of:

H=3b^2

And a width of

W=4b^4+2b-6

The area is

A=(3b^2)(4b^4+2b-6)

Operating:

A=(3b^2)*4b^4+(3b^2)*2b-(3b^2)6

A=12b^6+6b^3-18b^2

The area of the rectangle is A=12b^6+6b^3-18b^2

8 0
3 years ago
A man is sixteen years older than his father, if the total age is 57. How old is the son and the father?​
Alex Ar [27]

Answer:

The son is 20 and a half years old.

The father is 36 and a half years old.

Step-by-step explanation:

We can solve this easily by turning it into an equation.

Let the mans age be y and the fathers age be x.

y+x=57

x=y+16

We can use the substitution method to solve for the first equation.

y+(y+16)=57

Now we only have one variable to solve for. Add like terms.

2y+16=57

Subtract 16 on both sides.

2y=41

Divide both sides by 2 to isolate y.

y=20.5

Now substitute 20.5 for y to solve for x.

20.5+x=57

Subtract 20.5 from both sides.

x=36.5

<em>The son is 20 and a half years old.</em>

<em>The father is 36 and a half years old.</em>

Hope this helps!

8 0
3 years ago
10. When Raphael solved the system below by using the method of elimination, he changed the second equationto -8x – 2y = -2. Wha
Alex17521 [72]

\begin{gathered} 8x+3y=7\ldots eqn(1) \\ 4x+y=1\ldots.eqn(2) \end{gathered}

The property that justifies multiplying through eqn(2) by -2 is;

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5 0
1 year ago
How do I solve it because it’s really difficult
dybincka [34]

The solution of the equation is x= 3 and y = 2

Step-by-step explanation:

Given,

-3x-4y = -17 and

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The system of equation can be rewritten as

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x+3y = 9 ------ eq 2

To solve for x and y

Multiplying eq 2 by 3 we get,

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or, 3x = 27-9y

Putting this value of x into eq 1 we get,

27-9y +4y = 17

or, -5y = 17-27

or, -5y = -10

or, y = 2

Now put y=2 in eq 2 we get,

x = 9 - 3(2)

= 3

Hence the solution is x = 3 and y = 2

6 0
3 years ago
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