Answer:
D
Step-by-step explanation:
If you add 0 to anything, you do not have anything new when you are finished. A is an identity.
When you multiply 1 times anything, you do not get anything new. B is an identity
When you switch the order of two numbers and they are not affected by signs, then you are using the commutative property of addition. Nothing changes. C is an identity.
D is the problem child. Nothing I can think of right now will not change will you add 1 to it. If you can think of something that doesn't change when you add one to it, please put it in the comments. Otherwise, D is not an identity.
Answer:
not clear
Step-by-step explanation:
what is the height and base? need an image
Answer:
1 doller and 25 cents so easy
Step-by-step explanation:
Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
