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barxatty [35]
3 years ago
13

BRAINLIEST ASAP solve for y -140=18+4(5y-2)

Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

Variable Y is equal to 7.5.

Step-by-step explanation:

First, open the brackets:

18 + 20y - 8 = -140

Second, subtract 18 and add 8 from/to both sides.

20y = -140 - 18 + 8

20y = -150

Third, divide by 20.

y = 7.5

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Please solve the following sum or difference identity.
xxTIMURxx [149]

Answer:

sin(A - B) = \frac{4}{5}

Step-by-step explanation:

Given:

sin(A) = \frac{24}{25}

sin(B) = -\frac{4}{5}

Need:

sin(A - B)

First, let's look at the identities:

sum: sin(A + B) = sinAcosB + cosAsinB

difference: sin(A - B) = sinAcosB - cosAsinB

The question asks to find sin(A - B); therefore, we need to use the difference identity.

Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.

sin(A) = \frac{24}{25}

cos(A) = \frac{7}{25}

sin(B) = -\frac{4}{5}

cos(B) = \frac{3}{5}

Plug these values into the difference identity formula.

sin(A - B) = sinAcosB - cosAsinB

sin(A - B) = (\frac{24}{25})(\frac{3}{5}) - (-\frac{4}{5})(\frac{7}{25})

Multiply.

sin(A - B) = (\frac{72}{125}) + (\frac{28}{125})

Add.

sin(A - B) = \frac{4}{5}

This is your answer.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Calculate the product of 8/15, 6/5, and 1/3. 
Mariulka [41]
\frac{8}{15} * \frac{6}{5} * \frac{1}{3}

First, I would multiply the last two fractions because they're smaller and easier to work with:

\frac{8}{15} * \frac{6}{5} * \frac{1}{3} = \frac{8}{15} * \frac{6}{15}

Now that we've simplified it, we could multiply these terms and simplify.  An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:

\frac{8}{15} * \frac{6}{15} = \frac{8}{5} * \frac{2}{15}

We can now multiply these terms:

\frac{8}{5} * \frac{2}{15} =  \frac{16}{75}

The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>
5 0
3 years ago
Philip is making a poster that is 36 by 24 inches. He cuts a 5 x 12 rectangle in the poster. How much of the poster remains uncu
Vika [28.1K]
36 x 24=864 whole poster
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6 0
3 years ago
PLEASE HELP MEEEE HURRRY!!! :)
sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}  First, I swapped the first and third rows.

\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}  Leading coefficient of row 2 canceled.  

\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}  The start value of row 3 was canceled.

\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}       Matrix rows 2 and 3 were swapped.

\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}      Leading coefficient in row 3 was canceled.

\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}

The positioning of the zeros indicated that there was no solution!

<u><em>Hope that helps!</em></u>

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Among all pairs of numbers whose sum is 100, find a pair whose product is as large as
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Answer:

99+1

Step-by-step explanation:

8 0
2 years ago
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