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Butoxors [25]
3 years ago
14

60 points Need help Asap

Mathematics
1 answer:
Anna [14]3 years ago
8 0

Answer:

45 units ^2

Step-by-step explanation:

make sure to divide the triangle and sqaure up when finding the area of this polygon..

hope this helps!!

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What is the equation of the line in point slope form given a slope of -3 and a point of (-2,-5)?​
Lelu [443]

Answer:

y = -3x - 11

Step-by-step explanation:

Use the given slope and point in the point-slope equation. Solving this will give us the y-intercept equation.

Point-slope formula: y - y = m(x - x)

Plug in the slope and point

y - (-5) = -3(x - (-2))

Subtracting negatives will make them positive. Multiply out the -3 to what is in the parentheses.

y + 5 = -3x - 6

Subtract the 5 from both sides

y = -3x - 11

The equation of the line is y = -3x - 11

7 0
2 years ago
Please help me out with this
Olin [163]
The pattern is multiplying by 3. So it will be: 243, 729
4 0
2 years ago
Read 2 more answers
Please help I am really confused with this​
mario62 [17]

The answer should be A. 4 Meters

5 0
2 years ago
Substititue 5 for x. Is the solution true?<br> 3x + 4 - x = 4x - 6
Aloiza [94]

Answer:

It's a true solution.

Step-by-step explanation:

3(5) + 4 - 5 = 4(5) - 6

15 + 4 - 5 = 20 - 6

19 - 5 = 14

14 = 14

3 0
2 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0
3 years ago
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