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Lina20 [59]
3 years ago
11

Compute the difference​ quotient, StartFraction f (x plus h )minus f (x )Over h EndFraction f(x+h)−f(x) h​, for the function f (

x )equals 3 x squaredf(x)=3x2​, and simplify.
Mathematics
1 answer:
lawyer [7]3 years ago
4 0

Answer:

The difference quotient for f(x)=3x^2 is 3 h + 6 x.

Step-by-step explanation:

The difference quotient is a formula that computes the slope of the secant line through two points on the graph of <em>f</em>. These are the points with x-coordinates x and x + h. The difference quotient is used in the definition the derivative and it is given by

\frac{f(x+h)-f(x)}{h}

So, for the function f(x)=3x^2 the difference quotient is:

To find f(x+h), plug x+h instead of x

f\left(x+h\right)=3 \left(h + x\right)^{2}

Finally,

\frac{f\left(x+h\right)-f\left(x\right)}{h}=\frac{\left(3 \left(h + x\right)^{2}\right)-\left(3 x^{2}\right)}{h}

\frac{3\left(\left(h+x\right)^2-x^2\right)}{h} \\\\\frac{3(h^2+2hx+x^2-x^2)}{h} \\\\\frac{3h\left(h+2x\right)}{h}\\\\3h+6x

The difference quotient for f(x)=3x^2 is 3 h + 6 x.

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3/4=j-1/2 solve the equation check your solution
DIA [1.3K]
3/4= j-1/2
first to add 1/2 to both sides to solve for j 
3/4 + 1/2= j
second you find a common denominator in order to add 3/4 and 1/2, the common denominator would be 4, you would have to change 3/4 at all because the denominator is already 4 but in order to make the denominator of 1/2, 4 you would have to multiply both the denominator and numerator by 2 so 
3/4 + 2/4 = 5/4
so 5/4 =j

to check your answer you plug 5/4 in for j 
3/4 = 5/4 -1/2
again you need to find a common denominator between 5/4 and 1/2 which again would be 4, and again you wouldn't change 5/4 but you would multiply both the numerator and the denominator of 1/2 so 
3/4= 5/4-2/4
5-2= 3 and you would keep the 4 so 
5/4 - 2/4 = 3/4

so j =  5/4
5 0
2 years ago
PLEASE HELP, MATH, PLEASE<br>Solve for n: n+5/16 = -1​
Anit [1.1K]

\tt Step-by-step~explanation:

To solve for n, we have to isolate n. To do so, we move all the terms that are not n to one side of the equation, and leave n on the other side.

\tt Steps:

Equation: n + 5/16 = -1

Subtract 5/16 on both sides to bring it to the right side of the equation.

\tt n+5/16-5/16=-1-5/16\\\\n=-\frac{21}{16}~or~-1\frac{5}{16}

\Large\boxed{\tt Our~final~answer:~n=-\frac{21}{16}~or~-1\frac{5}{16} }

3 0
2 years ago
PLEASE HELP!!! THX
PSYCHO15rus [73]

Answer:  1) Product property of logarithm,

2) Subtraction property of logarithm

3) Equality property of logarithm

Step-by-step explanation:

By the Product property of logarithm,

log a + log b = log(a.b)

And, By the Subtraction property of logarithm

log a - log b = log(a/b)

Also, by the equality property of logarithm,

log(a) = log(b) ⇒ a = b

Given expression,

log_2(5)+log_2(x+2)-log_2(x+1)=log_2(7)                                                                

\implies log_2(5(x+2))-log_2(x+1))=log_2(7)  (Product property of logarithm)

\implies log_2(\frac{5(x+2)}{2(x+1)})=log_2(7)  (Subtraction property of logarithm)

\implies \frac{5(x+2)}{2(x+1)}=7   ( Equality property of logarithm )

\implies 5(x+2)=7(x+1)    ( Multiplicative property of equality )

\implies 5x+10=7x+7  ( Distributive property of equality )

\implies 3=2x    (subtraction property of equality )

x=\frac{3}{2}       (division property of equality )

3 0
3 years ago
Read 2 more answers
Determine if the following table represents a linear function. If so, what’s the rate of change?
VLD [36.1K]
Yes at the rate of change is 3/2
3 0
3 years ago
Read 2 more answers
Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda
pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

Step-by-step explanation:

Given equation is

x^2y'' - 9xy+24y=0

This Euler Cauchy type differential equation.

So, we can let

y=x^m

Differentiate with respect to x

y'= mx^{m-1}

Again differentiate with respect to x

y''= m(m-1)x^{m-2}

Putting the value of y, y' and y'' in the differential equation

x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0

\Rightarrow m(m-1)x^m-9mx^m+24x^m=0

\Rightarrow m^2-m-9m+24=0

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

y_1(x)=x^4

and

y_2(x)=x^6

First we compute the Wronskian

W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|

         = \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|

         =x⁴×6x⁵- x⁶×4x³    

        =6x⁹-4x⁹

        =2x⁹

       ≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

5 0
3 years ago
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