You must stop at the intersection and proceed when you are aware that other turning or approaching vehicles,bicycles or pedestrians have stopped.
Answer:
c. Full Sandbox
d. Partial Sandbox
e. Developer Pro
Explanation:
Universal Containers wants to use a sandbox with real data in it. Which Sandboxes three would you recommend?
a. Test Sandbox
c. Test Sandbox
c. Full Sandbox
d. Partial Sandbox
e. Developer Pro
From the question, we are informed that Universal Containers wants to use a sandbox with real data in it. In this case I will recommend Full Sandbox, Partial Sandbox and Developer Pro.
Sandboxes. In cybersecurity sandbox can be explained as security mechanism that is utilized to separate running programs, and this is an effort utilized to curb system failure as well as software vulnerabilities to disperse.
Sandboxes are crucial when executing suspicious code, it helps to do this so that the host device is is not put to risk of harm. Since, Containers wants to use a sandbox with real data in it then the three types of sandboxes can be use.
✓Full sandboxes allows performance testing as well as staging it can be regarded as copy of production org, and these can be objects attachment and others
✓Partial Copy Sandbox can be allows copying of configuration and part of one's data, in order to allow new configuration testing with one's real data.
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n;
double average,sum=0,x;
cout<<"enter the Value of N:";
// read the value of N
cin>>n;
cout<<"enter "<<n<<" Numbers:";
// read n Numbers
for(int a=0;a<n;a++)
{
cin>>x;
// calculate total sum of all numbers
sum=sum+x;
}
// calculate average
average=sum/n;
// print average
cout<<"average of "<<n<<" Numbers is: "<<average<<endl;
return 0;
}
Explanation:
Read the total number from user i.e "n".Then read "n" numbers from user with for loop and sum them all.Find there average by dividing the sum with n.And print the average.
Output:
enter the Value of N:5
enter 5 Numbers:20.5 19.7 21.3 18.6 22.1
average of 5 Numbers is: 20.44
Answer: Fixed layout
Explanation:
Fixed layout is the arrangement of any website page or webpage that is featured with fixed size on any screen resolution .Fixed layout displays all the components and tools of the page with a fixed percentage.
- The width or percentage cannot be changed or altered as it is fixed.The user experiences same width of the page and elements in any computing resolution.
Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.
