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DIA [1.3K]
3 years ago
10

Select the examples of common Arts, A/V Technology, and Communication employers. Check all that apply.

Computers and Technology
2 answers:
Zina [86]3 years ago
4 0

Answer:publication, telecommunications companies, movie studios, television networks

Explanation:

Just answered it on edg

jok3333 [9.3K]3 years ago
3 0

Answer:

publication, telecommunications companies, movie studios, television networks

Explanation:On edge2021

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Write a method maxMagnitude() with two integer input parameters that returns the largest magnitude value. Use the method in a pr
yawa3891 [41]

Answer:

The program in Java is as follows:

import java.util.*;

import java.lang.Math;

public class Main{

public static int maxMagnitude(int num1, int num2){

    int mag = num2;

    if(Math.abs(num1) > Math.abs(num2)){

        mag = num1;

    }

    return mag;

}

public static void main(String[] args) {

 int num1, num2;

 Scanner input = new Scanner(System.in);

 System.out.print("Enter two integers: ");

 num1 = input.nextInt();

 num2 = input.nextInt();

 System.out.println(maxMagnitude(num1,num2));

}

}

Explanation:

The method begins here

public static int maxMagnitude(int num1, int num2){

This initializes the highest magnitude to num2

    int mag = num2;

If the magnitude of num1 is greater than that of num2

    if(Math.abs(num1) > Math.abs(num2)){

mag is set to num1

        mag = num1;

    }

This returns mag

    return mag;

}

The main  method begins here

public static void main(String[] args) {

This declares num1 and num2 as integer

 int num1, num2;

 Scanner input = new Scanner(System.in);

This prompts the user for two integers

 System.out.print("Enter two integers: ");

This gets input for the first integer

 num1 = input.nextInt();

This gets input for the second integer

 num2 = input.nextInt();

This calls the maxMagnitude method and prints the number with the highest magnitude

 System.out.println(maxMagnitude(num1,num2));

}

3 0
3 years ago
Write a static generic method PairUtil.minmax that computes the minimum and maximum elements of an array of type T and returns a
Gnesinka [82]

Answer:

Explanation:

The following code is written in Java. It is hard to fully create the code without the rest of the needed code including the T class and the Measurable interface. Regardless the following code can be implemented if you have that code available.

 public static T minmax(ArrayList<T> mylist) {

       T min = new T();

       T max = new T();

       for (int x = 0; x < mylist.size(); x++) {

           if (mylist.get(x) > max) {

               max = mylist.get(x);

           } else if (mylist.get(x) < min) {

               min = mylist.get(x);

           }

       }

       

       return (min, max);

   }

5 0
3 years ago
Jake was working on an essay for his English class on a stormy Sunday afternoon. Before he could save his document, a big strike
matrenka [14]

Maybe in atosave, Computers mostly save what your working on :3

8 0
4 years ago
"assignment is to create a program that will read a value from an array, and then place this value in another array with the loc
White raven [17]

Answer:

#include <iostream>//including libraries

using namespace std;

int main()

{

int arr[6] = { 0,1,2,3,4,5 };//make sure size of arr is 1 less than secArr

int secArr[7];//second array (1 element bigger)

for (int i = 0;i < 6;i++)//looping through each element (6 times)

{

 secArr[i + 1] = arr[i];//transferring elements to second array and shifting by 1 cell

 cout << secArr[i + 1] << endl;//printing elements of second array

}

return 0;//terminating program

}

Explanation:

The array size can range from any number. just make sure to keep arr one less than secArr. This is because we need the room for the extra element. This task is to help you understand how array work and how to parse through them using loops. For loops are the best for this task because even if you think intuitively, they work for as long as there are items in the array. and you can define the size yourself.

5 0
3 years ago
There will be 10 numbers stored contiguously in the computer at location x 7000 . Write a complete LC-3 program, starting at loc
Artist 52 [7]

Answer:

The LC-3 (Little Computer 3) is an ISA definition for a 16-bit computer. Its architecture includes physical memory mapped I/O via a keyboard and display; TRAPs to the operating system for handling service calls; conditional branches on N, Z, and P condition codes; a subroutine call/return mechanism; a minimal set of operation instructions (ADD, AND, and NOT); and various addressing modes for loads and stores (direct, indirect, Base+offset, PC-relative, and an immediate mode for loading effective addresses). Programs written in LC-3 assembler execute out of a 65536 word memory space. All references to memory, from loading instructions to loading and storing register values, pass through the get Mem Adr() function. The hardware/software function of Project 5 is to translate virtual addresses to physical addresses in a restricted memory space. The following is the default, pass-through, MMU code for all memory references by the LC-3 simulator.

unsigned short int get Mem Adr(int va, int rwFlg)

{

unsigned short int pa;

// Warning: Use of system calls that can cause context switches may result in address translation failure

// You should only need to use gittid() once which has already been called for you below. No other syscalls

// are necessary.

TCB* tcb = get TCB();

int task RPT = tcb [gettid()].RPT;

pa = va;

// turn off virtual addressing for system RAM

if (va < 0x3000) return &memory[va];

return &memory[pa];

} // end get MemAdr

Simple OS, Tasks, and the LC-3 Simulator

We introduce into our simple-os a new task that is an lc3 Task. An lc3 Task is a running LC-3 simulator that executes an LC-3 program loaded into the LC-3 memory. The memory for the LC-3 simulator, however, is a single global array. This single global array for memory means that alllc3 Tasks created by the shell use the same memory for their programs. As all LC-3 programs start at address 0x3000 in LC-3, each task overwrites another tasks LC-3 program when the scheduler swaps task. The LC-3 simulator (lc3 Task) invokes the SWAP command every several LC-3 instruction cycles. This swap invocation means the scheduler is going to be swapping LC-3 tasks before the tasks actually complete execution so over writing another LC-3 task's memory in the LC-3 simulator is not a good thing.

You are going to implement virtual memory for the LC-3 simulator so up to 32 LC-3 tasks can be active in the LC-3 simulator memory without corrupting each others data. To implement the virtual memory, we have routed all accesses to LC-3 memory through a get Mem Adr function that is the MMU for the LC-3 simulator. In essence, we now have a single LC-3 simulator with a single unified global memory array yet we provide multi-tasking in the simulator for up to 32 LC-3 programs running in their own private address space using virtual memory.

We are implementing a two level page table for the virtual memory in this programming task. A two level table relies on referring to two page tables both indexed by separate page numbers to complete an address translation from a virtual to a physical address. The first table is referred to as the root page table or RPT for short. The root page table is a fixed static table that always resides in memory. There is exactly one RPT per LC-3 task. Always.

The memory layout for the LC=3 simulator including the system (kernel) area that is always resident and non-paged (i.e., no virtual address translation).

The two figures try to illustrate the situation. The lower figure below demonstrates the use of the two level page table. The RPT resident in non-virtual memory is first referenced to get the address of the second level user page table or (UPT) for short. The right figure in purple and green illustrates the memory layout more precisely. Anything below the address 0x3000 is considered non-virtual. The address space is not paged. The memory in the region 0x2400 through 0x3000 is reserved for the RPTs for up to thirty-two LC-3 tasks. These tables are again always present in memory and are not paged. Accessing any RPT does not require any type of address translation.

The addresses that reside above 0x3000 require an address translation. The memory area is in the virtual address space of the program. This virtual address space means that a UPT belonging to any given task is accessed using a virtual address. You must use the RPT in the system memory to keep track of the correct physical address for the UPT location. Once you have the physical address of the UPT you can complete the address translation by finding the data frame and combining it with the page offset to arrive at your final absolute physical address.

A Two-level page table for virtual memory management.

x7000 123F x7000 0042

x7001 6534 x7001 6534

x7002 300F x7002 300F

x7003 4005 after the program is run, memory x7003 4005

x7004 3F19

7 0
3 years ago
Read 2 more answers
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