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xz_007 [3.2K]
2 years ago
9

Tabitha defines a sphere as the set of all points equidistant from a single point. Is Tabitha's definition valid?

Mathematics
2 answers:
Advocard [28]2 years ago
5 0

definition is valid since center is exactly 1radius away from any point on the outersurface.

other figures do not fit this defn

Ipatiy [6.2K]2 years ago
4 0

Answer:

<h2>Tabitha's defintion is valid.</h2>

Step-by-step explanation:

Her definition is valid because the sphere is basically defined by its radius, which is the equidistant points towards a center. If points are not equidistant, then that's not a sphere.

Also, Tabitha is considering "a set of points" referring to infinite points on the surface of the sphere. The single point she mentioned is the center.

Therefore, Tabitha's definition is valid because she's considering all elements that define a sphere.

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Oliver sewed a quilt 3 2/3 feet long and 2 1/4 feet wide. what is the area of her quilt?
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Answer:

8.25 feet

Step-by-step explanation:

3 2/3 times 2 1/4 equals 8.25

4 0
2 years ago
The population of a town increases by 4 % every year . In the last year the population of the town was 110000.
TEA [102]

Answer:

114,400 and 118,976.

Step-by-step explanation:

Let's represent this using a function. Let's let:

P(y) represent the total population, and y represent the total number of years since last year.

We know that the population grows by 4% every year or 0.04 every year. This is exponential growth. We can write this as:

P(y)=110000(1.04)^y

Note that the coefficient is 110000 because that is the year we are starting with. Also, note that it is 1.04 because we are essentially adding .04 to the original population.

Anyways, to find the present population, set y equal to 1 (because 1 year after last year is the present year)

P(1)=110000(1.04)^1=114400

The present population is 114,400 people.

For next year, set y equal to 2 (2 years after last year is next year)>

P(2)=110000(1.04)^2=118976

The population next year will be 118,976 people.

3 0
3 years ago
In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for
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3 years ago
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Answer:

Hexagon

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