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sweet [91]
3 years ago
14

Formed elements in blood are ______, and plasma is _______. Select one: a. blood clots; proteins b. mostly lipids; the matrix c.

the cells; the liquid portion of blood d. lacking in protein; regulator of blood osmolality e. acellular; cellular
Biology
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

option A is correct

Explanation:

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Which division in the plant kingdom consists of plants that lack xylem and phloem? A) flowering vascular plants. B) nonflowering
Zepler [3.9K]
Answer - C

Nonvascular plants do not consist of xylem and phloem and they have their own mechanism of action for transport of water and other nutrients to their cells.
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2 years ago
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Define the term osmosis
astraxan [27]

a process by which molecules of a solvent tend to pass through a semipermeable membrane from a less concentrated solution into a more concentrated one, thus equalizing the concentrations on each side of the membrane.

8 0
3 years ago
1. The primary factors affecting population growth
DedPeter [7]

Answer:

C.emigration is the answer......

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2 years ago
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Okazaki fragments are formed on which strand?
Alecsey [184]

Answer:

The leading strand is continuously synthesized and is elongated during this process to expose the template that is used for the lagging strand (Okazaki fragments). During the process of DNA replication, DNA and RNA primers are removed from the lagging strand of DNA to allow Okazaki fragments to bind to.

Explanation:

Hope it helps

6 0
3 years ago
Sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous
Pavel [41]

Answer:

6,25%

Explanation:

Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:

Parents: Aa X Aa

Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)

Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:

A x A = 1/4 = 25%

A x a = 1/4 = 25%

a x A = 1/4 = 25%

a x a = 1/4 = 25%

The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:

1/4 × 1/4 = 1/16 = 0.0625 = 6.25%

It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.

6 0
3 years ago
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