<span>You can check all the rates on the number line by finding the quotient between the top rate and the bottom rate given and make sure that all of your quotients are equal to the given rate. </span>
Answer:
So estimate.
Really depends on what needs to be estimated, the answer or the overall equation.
So doing the real one first.
283/11 = 25 8/11
You can’t have “part” of a student so rounding this you can go up since 8 is more then half of 11
So 26 students
If you were to round the overall equation then you’d get
280 / 10 which is 28 students per class
So two options.
Volume = length x width x height
So,
Volume = 2 1/3in x 2in x 1 2/3in
Volume = 7/3in x 6/3in x 5/3in
Volume = 210/9in^3
Volume = 70/3in^3 or 23 1/3in^3
"Completing the square" is the process used to derive the quadratic formula for the general quadratic ax^2+bx+c=0. Suppose you did not know the value of a,b, or c of the quadratic...
ax^2+bx+c=0 You need a leading coefficient of one for the process to work, so you divide the whole equation by a
x^2+bx/a+c/a=0 now you move the constant to the other side of the equation
x^2+bx/a=-c/a now you halve the linear coefficient, square that, then add that value to both sides, ie, (b/(2a))^2=b^2/(4a^2)...
x^2+bx/a+b^2/(4a^2)=b^2/(4a^2)-c/a now the left side is a perfect square...
(x+b/(2a))^2=(b^2-4ac)/(4a^2) now take the square root of both sides
x+b/(2a)=±√(b^2-4ac)/(2a) now subtract b/(2a) from both sides
x=(-b±√(b^2-4ac))/(2a)
It is actually much simpler keeping track of everything when using known values for a,b, and c, but the above explains the actual process used to create the quadratic formula, which the above solution is. :)
